The equation of any plane through the line of intersection of he planes 2 x – y = 0 and 3 z – y = 0 or y – 3 z = 0 is
(2 x – y) + k (y – 3 z) = 0    ...(1)
or 2x – y + ky – 3 k z = 0
or 2x + (k – 1) y – 3 k z = 0
∴ this plane is perpendicular to the plane 4 x + 5 y – 3 z = 8.
∴ (2) (4) + (k – 1) (5) + (–3 k) (– 3) = 0    [∴ a₁ a₂ + b₁ b₂ + c₁ c₂ = 0]
∴ 8 + 5 k – 5 + 9 k = 0 or 14 k = –3

Putting this value of k in (1),  we get
or 14 (2 x – y) – 3 (y – 3 z) = 0
or  28 x – 14 y – 3 y + 9 z =0
or    28 x – 17 y + 9 z = 0
which is the required equation of the plane.