If the direction cosines of two lines are connected by the equations l + m + n = 0, l2 + m2 - n2 = 0, then the angle between the lines is
The equation of the plane which contains the origin and the line of intersection of the planes r · a = d1 and r · b = d2, is
r . (d1a + d2b) = 0
r . (d2a - d1b) = 0
r . (d2a + d1b) = 0
r . (d1a - d2b) = 0
B.
r . (d2a - d1b) = 0
Any plane passing through the intersection of the planes r · a = d1 and r - b = d2 is
It will pass through the origin, it
On substituting the value of in Eq. (i), we get
r . (d2a - d1b) = 0
which is the required plane.
If from a point P(a, b, c) perpendiculars PA and PB are drawn to YZ and ZX - planes, then the equation of the plane OAB is
bcx + cay + abz = 0
bcx + cay - abz = 0
- bcx + cay + abz = 0
bcx - cay + abz = 0
If (2, 7, 3) is one end of a diameter of the sphere x2 + y2 + z2 - 6x - 12y - 2z + 20 = 0, then the coordinates of the other end of the diameter are
(- 2, 5, - 1)
(4, 5, 1)
(2, - 5, 1)
(4, 5. - 1)
If a line segment OP makes angles of with X-axis and Y-axis, respectively. Then, the direction cosines are
If a plane passing through the point (2, 2, 1) and is perpendicular to the planes 3x + 2y + 4z + 1 = 0 and 2x + y + 3z + 2 = 0. Then, the equation of the plane is
2x - y - z - 1 = 0
2x + 3y + z - 1 = 0
2x + y + z + 3 = 0
x - y + z - 1 = 0
If the points (1, 2, 3) and (2, - 1, 0) lie on the opposite sides of the plane 2x + 3y - 2z = k, then
k < 1
k > 2
k < 1 or k > 2
1 < k < 2
The triangle formed by the tangent to the curve f (x) = x2 + bx - b at the point (1, 1) and the coordinate axes lies in the first quadrant. If its area is 2, then the value of b is
- 1
3
- 3
1
If a plane meets the coordinate axes at A, B and C such that the centroid of the triangle is (1, 2, 4), then the equation of the plane is
x + 2y + 4z = 12
4x + 2y + z = 12
x + 2y + 4z = 3
4x + 2y + z = 3
The volume of the tetrahedron included between the plane 3x + 4y - 5z - 60 = 0 and the coordinate planes is
60
600
720
400