If the angle between the line and the plane 2x - y + z + 4 = 0 is such that , then the value of p is
0
The ratio in which the plane y - 1 = 0 divides the straight line joining (1, - 1, 3) and (- 2, 5, 4) is
1 : 2
3 : 1
5 : 2
1 : 3
Equation of the line passing through i + j - 3k and perpendicular to the plane 2x - 4y + 3z + 5 = 0 is
The angle between the straight lines and x = 3r + 2; y = - 2r - 1; z = 2, where r is a parameter, is
Equation of the line through the point (2, 3, 1) and parallel to the line of intersection of the planes x - 2y - z + 5 = 0 and x + y + 3z = 6 is
Foot of the perpendicular drawn from the origin to the plane 2x - 3y + 4z = 29 is
(5, - 1, 4)
(7, - 1, 3)
(5, - 2, 3)
(2, - 3, 4)
D.
(2, - 3, 4)
Let the foot of the perpendicular in the 2x - 3y + 4z = 29 be P.
So, the point satisfy the given plane.
Since, OF is perpendicular to the given plane. Therefore, normal to the plane is parallel to OF.
On putting the value of in Eq.(i), we get
2(2k) - 3(- 3k) + 4(4k) = 29
Hence, foot of perpendicular is (2, - 3, 4).
The projection of the line segment joining (2, 0, - 3) and (5, - 1, 2) on a straight line whose direction ratios are 2, 4, 4, is