A body of 6 kg rests in limiting equilibrium on an inclined plane

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 Multiple Choice QuestionsMultiple Choice Questions

591.

Direction ratios of the line which is perpendicular to the lines with direction ratios - 1, 2, 2 and 0, 2, 1 are

  • 1, 1, 2

  • 2, - 1, 2

  • - 2, 1, 2

  • 2, 1, - 2


592.

If the angle between the planes r . mi^ - j^ + 2k^ + 3 = 0 and r . 2i^ - mj^ - k^ - 5 = 0 is π3, then m =

  • 2

  • ± 3

  • 3

  • - 2


593.

If the origin and the points P(2, 3, 4 ), Q(1, 2, 3) and R(x, y, z) are coplanar, then

  • x - 2y - z = 0

  • x + 2y + z = 0

  • x - 2y + z = 0

  • 2x - 2y + z = 0


594.

If lines represented by equation px2 - qy2 = 0 are distinct, then

  • pq > 0

  • pq < 0

  • pq = 0

  • p + q = 0


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595.

The equation of the plane through (- 1, 1, 2) whose normal makes equal acute angles with coordinate axes is

  • r. i^ + j^ + k^ = 2

  • r. i^ + j^ + k^ = 6

  • r. 3i^ - 3j^ + 3k^ = 2

  • r. i^ - j^ + k^ = 3


596.

If distance of points 2i^ + 3j^ + λk^  from the plane r . 3i^ + 2j^ + 6k^ = 13 is 5 units, then λ = n

  • 6, - 173

  •  6, 173

  • - 6, - 173

  •  - 6, 173


597.

ABC has vertices at A = (2, 3, 5), B = (-1, 3, 2) and C = λ, 5, μ. If the median through A is equally inclined to the axes, then the values of λ and μ respectively are

  • 10, 7

  • 9, 10

  • 7, 9

  • 7, 10


598.

A plane is flying horizontally at a height of 1 km from ground. Angle of elevation of the plane at a certain instant is 60°. After 20 s, angle of elevation is found 30°. The speed of plane is

  • 1003 m/s

  • 2003 m/s

  • 1003 m/s

  • 2003 m/s


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599.

The maximum horizontal range of a ball projected with a velocity of 40 m/s is (take g = 9.8m/s2)

  • 157 m

  • 127 m

  • 163 m

  • 153 m


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600.

A body of 6 kg rests in limiting equilibrium on an inclined plane whose slope is 30°. If the plane is raised to slope of 60°, then force (in kg-wt) along the plane required to support it is

  • 3

  • 23

  • 3

  • 33


B.

23

Let P be the force required to support the body and µ be the coefficient of friction

Case I

When plane make inclnaton of 30°

In this case, R = 6gcos(30°)

   μR = 6sin30°      limiting equilibrium μ = tan30° = 13

Case II

When plane raised to the slope of 60°

In this case,S = 6gcos60°, P + μS = 6gsin60° P + 136gcos60° = 6gsin60°        P = 6g32 - 123 = 23gHence, P = 23 k - wt


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