A gun projects a ball at the angle of 45° with the horizontal. If the horizontal range is 39.2 m, then the ball will rise to
9.8 m
4.9 m
2.45 m
19.6 m
The lines and are coplanar and then equation to the plane in which they lie, is
x + y + z = 0
x - y + z = 0
x - 2y + z = 0
x + y - 2z = 0
C.
x - 2y + z = 0
The lines will be coplanar, if
Add 3rd columnto first and it becomes twice the second and hence the determinant is zero, as the two columns are identical. Again, the equation ofthe plane in which they lie is
On adding 1st and 3rd columns and subtracting twice the 2nd, we get
Two parallel unlike forces of magnitudes 15N and 10N are acting at points A and B respectively. If C is the point of action of resultant, then AB/BC is
2/1
1/2
2/3
3/2
If a person A is moving with velocity 2 km/h, person B is moving with velocity 3 km/h and the angle between the direction of movements of A and B is 60°, then the velocity of A relative to B in the direction of A is
The point of intersection of line and plane x + y - z = 3 is
(2, 1, 0)
(7, - 1, - 7)
(1, 2, - 6)
(5, - 1, 1)
A particle is thrown with the velocity v with the angle a from the horizontal plane and its range on the horizontal plane is twice to themaximum height gained. Then, is equal to
9
5
2
1
The points 0, 2 + 3i, i - 2 - 2i in the argand plane are the vertices of a
rectangle
rhombus
trapezium
parallelogram
If the resultant of two forces of magnitude P and P acting on a particle is of magnitude P, then the angle between them is
60°
120°
90°
150°