A particle is dropped from a height 12 g metre and 4 s after anotherparticle is projected from the ground towards it with a velocity 4g ms. The time after which the second particle meets first is
4 s
2 s
1 s
A uniform ladder rests in limiting equilibrium with its lower end on a rough horizontal plane with coefficient of friction µ and its upper end against a smooth vertical wall. If is the inclination of the ladder with the wall, then is equal to
A plane which passes through the point (3, 2, 0) and the line is
x - y + z = 1
x + y + z = 5
x + 2y - z = 0
2x - y + z = 5
A.
x - y + z = 1
Any plane passing through (3, 2, 0) is
A(x - 3) + B(y - 2) + C(z - 0) = 0 ...(i)
Plane is passing through the line
Since, the given plane is passing through the line, therefore the DR's of the normal is perpendicular to the line.
On solving Eqs. (ii) and (iii), we get
On putting the values of A, B and C in Eq. (i), we get
x - y + z = 1
If the planes x + 2y + kz = 0 and 2x + y - 2z = 0, are at right angles, then the value of k is
2
- 2
The ratio in which the line joining (2, 4, 5), (3, 5, - 4) is divided by the yz-plane is
2 : 3
3 : 2
- 2 : 3
4 : - 3
The equation of line of intersection of planes 4x + 4y - 5z = 12, 8x + 12y - 13z = 32can be written as :
The equation of the plane, which makes with co-ordinate axes, a triangle with its centroid is :
A variable plane moves so that sum of the reciprocals of its intercepts on the co-ordinate axes is 1/2. Then the plane passes through :
(- 1, 1, 1)
(2, 2, 2)
(0, 0, 0)
The direction cosines l, m, n of two lines are connected by the relations l + m + n = 0, lm = 0, then the angle between them is :
0