If the equation of the locus of a point equidistant from the points (a1, b1) and (a2, b2) is (a1 - a2)r + (b1 - b2)y + c = 0, then the value of 'c' is
A tetrahedron has vertices at 0(0, 0, 0), A(1, 2, 1), B(2, 1, 3) and C(- 1, 1, 2). Then, the angle between the faces OAB and ABC will be
Distance between parallel planes 2x - 2y + z + 3 = 0 and 4x - 4y + 2z + 5 = 0, is
D.