Important Questions of Triangles Mathematics | Zigya

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 Multiple Choice QuestionsShort Answer Type

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341.

In the given Fig.,  if EF || DC || AB. Prove that:
AE over ED equals BF over FC


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 Multiple Choice QuestionsLong Answer Type

342. In the given Fig. PM is median of triangle PQR is the mid-point of PM and MN || QS.
Prove that: PS = SN = NR.

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343. The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of the first triangle is 9 cm, find the corresponding side of the second triangle.
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344. Two poles of height a metres and b metres are p metres apart. Prove that the height of the point of intersection of the lines joining the top of each pole to the foot of the opposite pole is given by fraction numerator ab over denominator straight a plus straight b end fraction metres.
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345. Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting AC in 1 and AD produced to E. Prove that EL = 2 BL.
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 Multiple Choice QuestionsShort Answer Type

346. Express x in terms of p, q and r.

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 Multiple Choice QuestionsLong Answer Type

347. ABCD is a trapezium in which AB is parallel to DC. If AC and BD intersect at E and triangle AED is similar to triangle BEC. Prove that AD = BC.
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 Multiple Choice QuestionsShort Answer Type

348.

In the given Fig. ∠CAB = 90° and AD is perpendicular to BC. If AC = 15 cm, AB = 20 cm and BD = 16 cm, find AD.

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 Multiple Choice QuestionsLong Answer Type

349. In the given Fig; ∠EBA = ∠CDA = 90°, BC = 12 cm, CD = 18 cm, CE = (3x - 2) cm and AC = (4x + 2) cm.

Show that ∆ECB is similar to ∆ACD. Hence, find the lengths of segments CE and AC.
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350. In ∆ABC, AD ⊥ BC and BE ⊥ AC.
Prove:
(i) ∆ACD ~ ∆BCE.
(ii) AC × CE = BC × CD.
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