The diagonals of a quadrilateral ABCD intersect each other at po

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 Multiple Choice QuestionsLong Answer Type

181. In the adjacent figure, if LM || CB and LN || CD, prove that AM over AB equals AN over AD


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182. In the given figure. DE || AC and DF || AE. Prove that
BF over FE equals BE over EC.

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183. In the given Fig. DE || OQ and DF || OR. Show that EF || QR.

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184. In the given fig, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show that BC || QR.

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 Multiple Choice QuestionsShort Answer Type

185. Prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side.

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186. Using Theorem 6.2 (N.C.E.R.T.), prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side.

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 Multiple Choice QuestionsLong Answer Type

187. ABCD is a trapezium in which AB || DC and its diagonals intersect each other at the point O. Show that  AO over BO equals CO over DO.

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188. The diagonals of a quadrilateral ABCD intersect each other at point O such that AO over BO equals CO over DO.  Show that ABCD is a trapezium.



Given a quadrilateral ABCD in which AC and BD are diagonals, which in
Given a quadrilateral ABCD in which AC and BD are diagonals, which intersect each other at O.
To Prove : ABCD is a trapezium such that AB || DC.
Const : Draw a line OM || AB.
Proof: In ∆ADB, we have OM || AB.
Therefore, by using Basic proportionality theorem, we have
                            DM over MA equals DO over OB

           rightwards double arrow space space space space space space space space space space space space AM over DM equals OB over OD space space space space space space space... left parenthesis straight i right parenthesis

[Taking reciprocals of both sides]
It is given that, 
                          space space space AO over BO equals CO over DO

rightwards double arrow                       AO over OC equals OB over OD         ...(ii)
Comparing (i) and (ii), we get
AM over DM equals OA over OC
Therefore, by using converse of basic proportionality theorem, we have
OM || DC
But    OM || AB (by construction)
⇒    AB || DC
Hence, ABCD is a trapezium.


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189. State which pairs of triangles in the given Fig, are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form:


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 Multiple Choice QuestionsShort Answer Type

190.

In the given fig. ∆ODC ~ ∆OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB.



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