To prove : ∆RPQ ~ ∆RTS.
Proof : In ∆RPQ and ∆RTS, we have,
∠RPQ = ∠RTS [Given].
and ∠QRP = ∠SRT [Common]
Therefore by using AA similar condition.
∆RPQ ~ ∆RTS.
In the given Fig, altitudes AD and CE of intersects each other at the point P. Show that:
(i) ∆AEP ~ ∆CDP
(ii) ∆ABD ~ ∆CBE
(iii) ∆AEP ~ ∆ADB
(iv) ∆PDC ~ ∆BEC.
In the given fig, ABC and AMP are two right triangles, right angled at B and M respectively.
Prove that:
(i)
(ii)
CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. If ΔABC ~ ΔFEG, show that:
(i)
(ii)
(iii)
In the given fig, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC. Prove that ∆ABD ~ ∆ECF.