Prove that the ratio of the areas of two similar triangle is equ

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 Multiple Choice QuestionsLong Answer Type

201.

In the given fig, D is a point on the side BC of ∆ABC such that ∠ADC = ∠BAC. Prove that <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>  or  CA2 = CB.CD.


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202. Sides AB and AC and median AD of triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that ∆ABC ~ ∆PQR.
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203. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
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204. If AD and PM are medians of triangles ABC and PQR, respectively where ∆ABC ~ ∆PQR, prove that <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
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#6 {main}</pre>
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 Multiple Choice QuestionsShort Answer Type

205. Let ∆ABC ~ ∆DEF and their areas be, respectively, 64 cm2 and 121 cm2. If EF = 15.4 cm, find BC.
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206.

Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O.If AB = 2 CD, find the ratio of the areas of triangles AOB and COD.

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 Multiple Choice QuestionsLong Answer Type

207.

In the given fig, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show thatspace space fraction numerator ar left parenthesis increment ABC right parenthesis over denominator ar left parenthesis increment DBC right parenthesis end fraction equals AO over DO.

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208. If the areas of two similar triangles are equal, then the triangles are congruent i.e., equal and similar triangles are congruent.
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209. D, E, F are respectively the mid-points of sides AB, BC and CA and of ∆ABC. Find the ratio of the areas of ∆DEF and ∆ABC.
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210. Prove that the ratio of the areas of two similar triangle is equal to the square of the ratio of their corresponding medians.



Given: ∆ABC and ∆DEF such that ∆ABC ~ DEF. AP and DQ are median

Given: ∆ABC and ∆DEF such that ∆ABC ~ DEF. AP and DQ are medians drawn on sides BC and EF respectively.
To Prove:  fraction numerator ar left parenthesis increment ABC right parenthesis over denominator ar left parenthesis increment DEF right parenthesis end fraction equals AP squared over DQ squared
Proof:    ∵      <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>
rightwards double arrow    fraction numerator ar left parenthesis increment ABC right parenthesis over denominator ar left parenthesis increment DEF right parenthesis end fraction equals AB squared over DE squared                  ...(i)
We have
                        AB over DE equals BC over EF space left square bracket because space space space increment ABC space tilde space increment DEF right square bracket

rightwards double arrow                    AB over DE equals fraction numerator 2 BP over denominator 2 EQ end fraction

rightwards double arrow                  AB over DE equals BP over EQ
Now, in ∆ABP and ∆DEQ
                    AB over DE equals BP over EQ
and                    <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>
Therefore, by using SAS similar condition
          increment ABP tilde increment DEQ
space space rightwards double arrow space space space space space space space space space space space space space space space space space space AB over DE equals AP over DQ
space rightwards double arrow space space space space space space space space space space space space space space space space space space AB squared over DE squared equals AP squared over DQ squared space space... left parenthesis ii right parenthesis
Comparing (i) and (ii), we have
                    space fraction numerator ar left parenthesis increment ABC right parenthesis over denominator ar left parenthesis increment DEF right parenthesis end fraction equals AP squared over DQ squared.

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