∵  In triangle ABC, DE || BC
∴  By Basic Proportionality Theorem
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In the given fig.,  and ∠PST = ∠PRQ. Prove that ∆PQR is an isosceles triangle.
In the given fig, ∆ABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB2 = BC. BD.
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