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Triangles

Short Answer Type

241. In Fig. DE || BC and

space AD over DB equals 3 over 5.

If AC = 4.8 cm, find the length of AE.

652 Views

242. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ∆ABE ~ ∆CFB.

862 Views

243.

In the given fig., $PS over SQ equals PT over TR$ and ∠PST = ∠PRQ. Prove that ∆PQR is an isosceles triangle.

219 Views

244.
In the given fig, ∆ABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB² = BC. BD.

In ∆ABD and ∆CBA

angle straight A space equals space angle straight C

open square brackets each space equals space 90 degree close square brackets

angle straight B space equals space angle straight B space space space space space space space space space left square bracket Common right square bracket

∴

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rightwards double arrow space space space space space space space space space space space space space space space space AB over BC equals BD over AB rightwards double arrow space space space space space space space space space space space space space space space space space space AB squared space equals space BC. space BD space Proved

201 Views

245.

In the given fig, AB || DC. Find the value of x.

1047 Views

246.

In the given fig, express x in terms of a, b and c.

2955 Views

247.

In the given fig, $OA over OC equals OD over OB.$ Prove that ∠A = ∠C and ∠B = ∠D.

82 Views

Long Answer Type

248. The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA.

1489 Views

Short Answer Type

249. In a ∠ABC, BD and CE are the altitudes. Prove that ∠ADB and ∠AEC are similar. Is ∆CDB ~ ∆BEC?

403 Views

250. The perimeters of two similar triangles ABC and PQR are respectively 36 cm and 24 cm. If PQ = 10 cm, find AB.

162 Views

Previous Year Papers

Test Series

Test Yourself

Short Answer Type

244. In the given fig, ∆ABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB2 = BC. BD.

Long Answer Type

Short Answer Type

244.
In the given fig, ∆ABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB² = BC. BD.