In the given Fig, two triangles ABC and DBC lie on the same side of base BC. P is a point on BC such that PQ || BA and PR || BD. Prove that: QR || AD.
In the given fig, ST || QR, PS = 2 cm and SQ = 3 cm. What is the ratio of the area of ∆PQR to the area of ∆PST?
In the given Fig. PB and QA are perpendiculars to segment AB. If PO = 5 cm, QO = 7 cm and area ∆POB = 150 cm2 find the area of ∆QOA.
In ∆OAQ and ∆OBP, we have
∠A = ∠B [Each equal to 90°]
∠AOQ = ∠BOP [Vert.opp.angles]
Therefore by using AA similar condition, we have
In the given fig, DE is parallel to BC and AD = 1 cm, BD = 2 cm. What is the ratio of the area of ∆ABC to the area of ∆ADE?