291.Any point X inside ∆DEF is joined to its vertices. From a point P in DX, PQ is drawn parallel to DE meeting XE in Q and QR is drawn parallel to EF meeting XF in R. Prove that PR || DF.
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292.Let ABC be a triangle and D and E be two points on side AB such that AD = BE, then prove that PQ || AB.
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293.In a ∆ABC, D and E are points on sides AB and AC respectively such that BD = C’E. If ∠B = ∠C, show that DE || BC.
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294.Let X be any point on the side BC of a triangle ABC. If XM, XN are drawn parallel to BA and CA meeting CA, BA in M and N respectively, MN meets BC produced in T. Prove that TX2 = TB × TC.
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295.The side BC of a triangle ABC is bisected at D; O is any point in AD. BO and CO produced meet AC and AB in E and F respectively and AD is produced to X, So that D is the midpoint of OX. Prove that AO: AX = AF : AB and show that FE || BC.
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296.In the given figure: if and ∠CDE = ∠CED. Prove that ∆CAB is isosceles.
297.P is the mid-point of side BC of ∆ABC. Q is the mid-point of AP. BQ when produced meets AC at L. Prove that
Given: A ∆ABC in which P is the mid-point of side BC, Q is the mid point of AP and BQ when produced meets AC in L. To Prove: Const: Draw PM || BL Proof : In ∆BCL, we have PM || BL Therefore, by using Basic proportionality theorem, we have
...(i) But ...(ii) Comparing (i) and (ii), we get
...(iii) Now in ∆APM, we have QL || PM Therefore, by using Basic prportionality theorem, we have ...(iv) But ...(v) Comparing (iv) and (v), we get
...(vi) Comparing (iii) and (vi), we have
Now,
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298.ABCD is a quadrilateral P, Q, R, S are the points of trisection of the sides AB, CB, CD and AD respectively. Prove that PQRS is a parallelogram.
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Short Answer Type
299.
In the given Fig, AB || DE and BC || EF. Prove that AC || DF.
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Long Answer Type
300.Two triangles BAC and BDC, right angled at A and D respectively are drawn on the same base BC and on the same side of BC. If AC and DB intersect at E, prove that AE × EC = BE × DE.