In a right triangle ABC, right angled at C.P. and Q are the poin

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 Multiple Choice QuestionsLong Answer Type

321. Prove that three times the sum of the squares of the sides of a triangle is equal to four times the sum of the squares of the medians of the triangle.



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322. Points P, Q, R and S in that order are dividing a line segment joining A(2, 6) and B(7, 4) in five equal parts. Find the co-ordinates of P and R.
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323. BL and CM are median of a triangle ABC right angled at A. Prove that 4(BL2 + CM2) = 5BC2.

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324.

In the given Fig, ABC is a right triangle, right angled at B. AD and CE are  two medians drawn from A and C respectively. If AC = 5 cm and AD equals fraction numerator 3 square root of 5 over denominator 2 end fraction cm comma find the length of CE.


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 Multiple Choice QuestionsShort Answer Type

325. In an isosceles triangle ABC, with AB = AC, BD is perpendicular from B to the side AC. Prove that BD2 - CD2 = 2CD.AD.
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 Multiple Choice QuestionsLong Answer Type

326. ABC is a triangle in which AB = AC and D is any point in BC. Prove that AB2 - AD2 = BD.CD.
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327. In a right triangle ABC, right angled at C.P. and Q are the points on the sides CA and CB respectively, which divdes these sides in the ratio 2:1. Prove that
(i) 9AQ2 9AC2 + 4BC2
(ii) 9BP2 9BC2 + 4AC2
(iii) 9(AQ2 + BP2) = 13AB2.


Given: A right triangle ABC, right angled at CP and Q are the points on the sides AC and BC and dividing these sides in the ratio 2:1.

Given: A right triangle ABC, right angled at CP and Q are the points
Proof: ∵ P divides AC in the ratio of 2 : 1 and Q divides BC in the ratio of 2 : 1

Given: A right triangle ABC, right angled at CP and Q are the points   

Given: A right triangle ABC, right angled at CP and Q are the points

        
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328. In the given figure ABC is a triangle right angled at B. P and Q trisect BC. Prove that: 8AP2 = 3AC2 + 5AQ2
 
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329.

In the given Fig., ∠ACB = 90° and CD ⊥ AB. Prove that BC squared over AC squared equals BD over AD.





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330. P and Q are points on sides CA and CB respectively of ∆ABC, right angled at C. Prove that AQ2 + BP2 = AB2 + PQ2.
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