In the given Fig, DE || BC and DE divides ∆ABC in two parts s

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 Multiple Choice QuestionsLong Answer Type

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391.

In the given Fig, DE || BC and DE divides ∆ABC in two parts such that ar (∆ADE) = 1 third area space increment ABC, prove that  space BD over AB equals fraction numerator square root of 3 minus 1 over denominator square root of 3 end fraction.


Solution not provided.

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 Multiple Choice QuestionsShort Answer Type

392. In the given fig. DE||BC and AD: DB = 3:4
Find (i)   fraction numerator area space left parenthesis increment DEF right parenthesis over denominator area thin space left parenthesis increment CFB right parenthesis end fraction

and (ii)   fraction numerator area left parenthesis increment ADE right parenthesis over denominator area left parenthesis increment ABC right parenthesis end fraction



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 Multiple Choice QuestionsLong Answer Type

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(A)    Prove that PB2 + PD2 = PA2 + PC2.
(B)    If PA, PB and PC are 3 cm, 4 cm and 5 cm respectively, find the length of PD.
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 Multiple Choice QuestionsShort Answer Type

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