In figure, AB >  AC, BO and CO are the bisectors of ∠B and

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

Advertisement

501. In figure, AB >  AC, BO and CO are the bisectors of ∠B and ∠C respectively. Show that OB >  OC.



Given: AB >  AC, BO and CO are the bisectors of ∠B and ∠C respectively.
To Prove: OB >  OC
Proof: ∵ AB >  AC    | Given
∴ ∠ACB >  ∠ABC
| Angle opposite to longer side is greater


rightwards double arrow space space 1 half space angle A C B greater than 1 half angle A B C
rightwards double arrow space space space angle O C B space greater than space angle O B C
therefore space space space space O B greater than O C

| Side opposite to greater angle is longer

1077 Views

Advertisement
502.

In the given figure, ∠ABD = 130° and ∠EAC = 120°. Prove that AB >  AC.

315 Views

503. If AD is the bisector of ∠A of ∆ ABC, show that AB > DB.
111 Views

 Multiple Choice QuestionsLong Answer Type

504. 0 is a point in the interior of ∆PQR.

OP + OQ + OR > 1 half (PQ + QR + RP).
1543 Views

Advertisement

 Multiple Choice QuestionsShort Answer Type

505. In figure, D is any point on the base BC produced of an isosceles triangle ∆ABC. Prove that AD > AB.


1992 Views

506. In figure, S is any point in its interior of ∆PQR. Show that SQ + SR <  PQ + PR.


3493 Views

507. Prove that the difference of any two sides of a triangle is less than the third side.
7200 Views

 Multiple Choice QuestionsMultiple Choice Questions

508. In the following figure, ∠B > ∠A and ∠D > ∠E. Then, the relation between AE and BD is


  • AE = BD
  • AE >  BD
  • AE <  BD 
  • AE <  BD 
94 Views

Advertisement
509. In ∆ABC, AB > AC and D is any point on side BC. Then, the relation between AB and AD is


  • AB >  AD
  •  AB = AD
  • AB <  AD
  • AB <  AD
90 Views

510. In the following figure, in ∆ABC, AB = AC; CD = CA and ∠ADC = 20°. Then, ∠ABC =


  • 10°
  • 20°
  • 30°
  • 30°
124 Views

Advertisement