Prove that the area of an equilateral triangle described on one s

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 Multiple Choice QuestionsMultiple Choice Questions

511. In ∆ABC and ∆DEF, if AB = DF, BC = DE, AC = EF and ∆D = 55°. Then, ∠B =
  • 55°
  • 35°
  • 90°
  • 90°
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512. In the following figure, ∠B = ∠D = 90° and BC = CD. Then, the relation between AB and DE is


  • AB = DE  
  • AB > DE
  • AB < DE 
  • AB < DE 
  • AB < DE 
163 Views

513.  In ∆ABC, AB = AC, BD = EC. Then, ∆ADE is


  • right angled
  • scalene
  • isosceles
  • isosceles
120 Views

 Multiple Choice QuestionsShort Answer Type

514.

Show that ΔABC, where A(–2, 0), B(2, 0), C(0, 2) and ΔPQR where P(–4, 0), Q(4, 0), R(0, 2) are similar triangles. 

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515.

Given ABC ~ PQR, if ABPQ = 13, then find arABCarPQR


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516.

Prove that the area of an equilateral triangle described on one side of the square is equal to half the area of the equilateral triangle described on one of its diagonal.


Given: Square ABCD with diagonal BD △ BCE which is described on base BC △ BDF which is described on base BD both △ BCE and △ BDF equilateral

To prove:

Proof:
Both △ BCE and △ BDF equilateral

In △ BDF and △ BCE

Hence by SSS similarity

△ FBD ~ △ BCE

We know that in similar triangles,

Ratio of area of a triangle is equal to the ratio of the square of the corresponding sides

But DB = √2 BC as DB is the diagonal of square ABCD

Hence,


Hence Proved


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517.

If the area of two similar triangles are equal, prove that they are congruent.


 Multiple Choice QuestionsLong Answer Type

518.

In an equilateral △ABC, is a point on side BC such that BD =1/3BC. Prove that 9 (AD)2 = 7(AB)2


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519.

Prove that, in a right triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides.


 Multiple Choice QuestionsMultiple Choice Questions

520.

ABCD is a rectangle whose three vertices are B (4, 0), C(4,3) and D(0, 3). The length of one of its diagonals is

  • 5

  • 4

  • 3

  • 25


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