Prove that, in a right triangle, the square on the hypotenuse is

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 Multiple Choice QuestionsMultiple Choice Questions

511. In ∆ABC and ∆DEF, if AB = DF, BC = DE, AC = EF and ∆D = 55°. Then, ∠B =
  • 55°
  • 35°
  • 90°
  • 90°
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512. In the following figure, ∠B = ∠D = 90° and BC = CD. Then, the relation between AB and DE is


  • AB = DE  
  • AB > DE
  • AB < DE 
  • AB < DE 
  • AB < DE 
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513.  In ∆ABC, AB = AC, BD = EC. Then, ∆ADE is


  • right angled
  • scalene
  • isosceles
  • isosceles
120 Views

 Multiple Choice QuestionsShort Answer Type

514.

Show that ΔABC, where A(–2, 0), B(2, 0), C(0, 2) and ΔPQR where P(–4, 0), Q(4, 0), R(0, 2) are similar triangles. 

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515.

Given ABC ~ PQR, if ABPQ = 13, then find arABCarPQR


516.

Prove that the area of an equilateral triangle described on one side of the square is equal to half the area of the equilateral triangle described on one of its diagonal.


517.

If the area of two similar triangles are equal, prove that they are congruent.


 Multiple Choice QuestionsLong Answer Type

518.

In an equilateral △ABC, is a point on side BC such that BD =1/3BC. Prove that 9 (AD)2 = 7(AB)2


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519.

Prove that, in a right triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides.


Given: A right -angled triangle ABC in which ∠B = 90°

To Prove: (Hypotenuse)2 = (Base)2 + (perpendicular)2

i.e, AC2 = AB2 +BC2

Construction: From B draw BD ⊥ AC

Proof: In triangle ADB and ABC, we have

img src="/application/zrc/images/qvar/MAEN10174967-1.png" width=" " height=" " >


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 Multiple Choice QuestionsMultiple Choice Questions

520.

ABCD is a rectangle whose three vertices are B (4, 0), C(4,3) and D(0, 3). The length of one of its diagonals is

  • 5

  • 4

  • 3

  • 25


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