In any quadrilateral ABCD, show that sin (A + B) + sin (C + D) =

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 Multiple Choice QuestionsShort Answer Type

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51. In any quadrilateral ABCD, show that sin (A + B) + sin (C + D) = 0.


ABCD is a quadrilateral

rightwards double arrow            space space space straight A plus straight B plus straight C plus straight D space equals space 360 degree space equals space 2 straight pi

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rightwards double arrow           sin left parenthesis straight A plus straight B right parenthesis space equals space sin left square bracket 2 straight pi space minus space left parenthesis straight C space plus straight D right parenthesis right square bracket

x is quadrant IV means sinx is -ve.

∴              sin (A + B) = sin[2straight pi - (C + D)] = - sin (C + D)

Hence, sin (A + B) + sin (C + D) = 0

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52. If A, B, C, D are the vertices of a cyclic quadrilateral, show that sin A + sin B - sin C - sin D = 0.
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53.

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54. Find the period of the following trigonometric functions:

sin open parentheses fraction numerator 3 straight x over denominator 2 end fraction close parentheses
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55. Find the period of the following trigonometric functions:

tan open parentheses fraction numerator 5 straight x over denominator 3 end fraction close parentheses


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56.

Show that: cos open parentheses fraction numerator 3 straight pi over denominator 2 end fraction plus straight x close parentheses space cos left parenthesis 2 straight pi plus straight x right parenthesis space open square brackets cot open parentheses fraction numerator 3 straight pi over denominator 2 end fraction minus straight x close parentheses plus cot left parenthesis 2 straight pi plus straight x right parenthesis close square brackets space equals space 1

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57. Find the value of:

sin open parentheses straight pi over 12 close parentheses
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58. Find the value of:

space space space cos open parentheses fraction numerator 5 straight pi over denominator 12 end fraction close parentheses

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59. Find the value of:

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60.

Prove that:

cos open parentheses fraction numerator 3 straight pi over denominator 4 end fraction plus straight x close parentheses minus space cos open parentheses fraction numerator 3 straight pi over denominator 4 end fraction minus straight x close parentheses space equals space minus square root of 2 sinx

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