The solution set of 5 + 4cosθ

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

931.

The solution set of 5 + 4cosθ2cosθ + 1 = 0 in the interval 0, 2π, is :

  • π3, 2π3

  • π3, π

  • 2π3, 4π3

  • 2π3, 5π3


C.

2π3, 4π3

We have, 5 + 4cosθ2cosθ + 1 = 0     ...i                                cosθ  = 1 - tan2θ21 +  tan2θ2,                              cosθ = 1 - t21 + t2      put  tanθ2 = tThen Eq.i beecomes             5 + 41 - t21 + t221 - t21 + t2 +1 = 0  5 + 5t2 + 4 - 4t22 - 2t2 + 1 + t2 = 0                                       t2 + 93 - t2 = 0                                                               t = ± 3 tanθ2 = 3 or tanθ2 = - 3 

 θ2 = π3 or θ2 = 2π3        θ = 2π3 or  4π3


Advertisement
932.

If tan3AtanA = a, then sin3AsinA is equal to

  • 2aa + 1

  • 2aa - 1

  • aa + 1

  • aa - 1


933.

If cos(A - B) = 3/5 and tan(A)tan(B) = 2, then which one of the following is true ?

  • sinA + B = 15

  • sinA + B = - 15

  • cosA - B = 15

  • cosA + B = - 15


934.

The angle of elevation of an object from a point P on the level ground is α. Moving d metres on the ground towards the object, the angle of elevation is found to be β. Then the height (in metres) of the object is

  • dtanα

  • dcotβ

  • dcotα + cotβ

  • dcotα - cotβ


Advertisement
935.

A vertical pole subtends an angle tan-112 at a point P on the ground. If the angles substended by the upper half and the lower half of the pole at P are respectively α and β , then tanα, tanβ is equal to

  • 14, 15

  • 15, 29

  • 29, 14

  • 14, 29


Advertisement