Let OB = and OA = . The distance of the point B from the straight line passing through A and parallel to the vector is
Let the position vectors of the points A, B and C be a, b and c, respectively. Let Q be the point of intersection of the medians of the . Then, QA + QB + QC is equal to
2a + b + c
a + b + c
0
A force of magnitude 5 unit acting along the vector displaces the point of application from (1, 2, 3) to (5, 3, 7). Then the work done is :
50/7 unit
50/3 unit
25/3
25/4