If  are unit vectors, and  is the angle between them, find 

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 Multiple Choice QuestionsShort Answer Type

161.

Prove that open vertical bar straight a with rightwards arrow on top close vertical bar space straight b with rightwards arrow on top space plus space open vertical bar straight b with rightwards arrow on top close vertical bar space straight a with rightwards arrow on top is orthogonal to open vertical bar straight a with rightwards arrow on top close vertical bar space straight b with rightwards arrow on top space minus space open vertical bar straight b with rightwards arrow on top close vertical bar space straight a with rightwards arrow on top, for any vectors straight a with rightwards arrow on top space and space straight b with rightwards arrow on top.

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162.

Prove that
left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis. space open parentheses straight a with rightwards arrow on top space plus space straight b with rightwards arrow on top close parentheses space equals space open vertical bar straight a with rightwards arrow on top close vertical bar squared plus space open vertical bar straight b with rightwards arrow on top close vertical bar squared
if and only if straight a with rightwards arrow on top comma space straight b with rightwards arrow on top are orthogonal.

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163.

Let straight a with rightwards arrow on top space and space straight b with rightwards arrow on top be the two non-zero vectors. Then, prove that straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are perpendicular if and only if open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top close vertical bar space equals space open vertical bar straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top close vertical bar.

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164.

Prove that two vectors straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are perpendicular if 
       open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top close vertical bar squared space equals space open vertical bar straight a with rightwards arrow on top close vertical bar squared plus space open vertical bar straight b with rightwards arrow on top close vertical bar squared

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165.

If straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are perpendicular, then left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis squared space equals space left parenthesis straight a with rightwards arrow on top minus straight b with rightwards arrow on top right parenthesis squared
 

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 Multiple Choice QuestionsLong Answer Type

166.

If open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 space and space open vertical bar straight c with rightwards arrow on top close vertical bar space equals 5 such that each is perpendicular to sum of the other two, find open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar.

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 Multiple Choice QuestionsShort Answer Type

167.

Find open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar comma space if two vectors straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are such that open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 2 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 3 space and space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 4.

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168.

Find open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar comma if open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 2 comma space space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 5 space space and space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 8

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169.

Find open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar squared if open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 space and space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 1.

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170.

If straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are unit vectors, and straight theta is the angle between them, find 1 half open vertical bar straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top close vertical bar in terms of straight theta.


We have
      open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar squared space equals space left parenthesis straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top right parenthesis squared space equals space straight a with rightwards arrow on top squared plus straight b with rightwards arrow on top squared space minus space 2 space straight a with rightwards arrow on top. space straight b with rightwards arrow on top
                     equals space open vertical bar straight a with rightwards arrow on top close vertical bar squared plus space open vertical bar straight b with rightwards arrow on top close vertical bar squared space minus space 2 space open vertical bar straight a with rightwards arrow on top close vertical bar space open vertical bar straight b with rightwards arrow on top close vertical bar space cos space straight theta
equals space left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared space minus space 2 left parenthesis 1 right parenthesis thin space left parenthesis 1 right parenthesis space cos space straight theta
                                            open square brackets because space open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 1 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 1 space as space straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space are space unit space vectors close square brackets
                 equals space 2 left parenthesis 1 minus cos space straight theta right parenthesis space equals space 2 space open parentheses 2 space sin squared space straight theta over 2 close parentheses
therefore space space space space open vertical bar straight a with rightwards arrow on top space minus straight b with rightwards arrow on top close vertical bar squared space equals space 4 space sin squared space straight theta over 2
therefore space space space space sin space straight theta over 2 space equals 1 half space open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar space space space space space space space space space space space open square brackets because space space 0 space less or equal than space straight theta space less or equal than space straight pi space space rightwards double arrow space space sin space straight theta over 2 greater or equal than space 0 close square brackets
because space space space space 1 half open vertical bar straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top close vertical bar space equals space sin space straight theta over 2.
    

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