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Vector Algebra

Long Answer Type

211.

If $straight a with rightwards arrow on top comma space straight b with rightwards arrow on top comma space straight c with rightwards arrow on top$ are unit vectors such that $straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top space equals space 0$ , then find the value of $straight a with rightwards arrow on top. straight b with rightwards arrow on top plus straight b with rightwards arrow on top. straight c with rightwards arrow on top plus straight c with rightwards arrow on top. straight a with rightwards arrow on top.$

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212. Three vectors

straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top

satisfy the condition

straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top space equals 0 with rightwards arrow on top.

Evaluate the quantity

straight mu space equals space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space plus straight b with rightwards arrow on top. space straight c with rightwards arrow on top space plus space straight c with rightwards arrow on top. space straight a with rightwards arrow on top comma space if space open vertical bar straight a with rightwards arrow on top close vertical bar space equals 1 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 space and space open vertical bar straight c with rightwards arrow on top close vertical bar space equals space 2.

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Short Answer Type

213.
Let $straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top$ be three vectors such that $open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 comma space space open vertical bar straight c with rightwards arrow on top close vertical bar space equals 5$ and each one of them being perpendicular to the sum of the other two, find $open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar.$

We have
$open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 comma space space space open vertical bar straight c with rightwards arrow on top close vertical bar space equals space 5$ ...(1)
Since $straight a with rightwards arrow on top$ is perpendicular to $straight b with rightwards arrow on top plus straight c with rightwards arrow on top comma space straight b with rightwards arrow on top$ is perpendicular $straight c with rightwards arrow on top plus straight a with rightwards arrow on top$ and $straight c with rightwards arrow on top$ is perpendicular to $straight a with rightwards arrow on top plus straight b with rightwards arrow on top$ .
$therefore space space space straight a with rightwards arrow on top. space left parenthesis straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis space equals space straight b with rightwards arrow on top. space left parenthesis straight c with rightwards arrow on top plus straight a with rightwards arrow on top right parenthesis space equals space straight c with rightwards arrow on top. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis space equals space 0 therefore space space space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space plus space straight a with rightwards arrow on top. space straight c with rightwards arrow on top space equals space straight b with rightwards arrow on top. space straight c with rightwards arrow on top space plus space straight b with rightwards arrow on top. space straight a with rightwards arrow on top space equals space straight c with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 0 space space space space space space space space... left parenthesis 2 right parenthesis$
Now, $open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar squared space equals space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis$
$equals space straight a with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space plus space straight a with rightwards arrow on top. space straight c with rightwards arrow on top space plus space straight b with rightwards arrow on top. straight a with rightwards arrow on top space plus space straight b with rightwards arrow on top. space straight b with rightwards arrow on top space plus space straight b with rightwards arrow on top. space straight c with rightwards arrow on top space plus space straight c with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top. space straight b with rightwards arrow on top plus space straight c with rightwards arrow on top. space straight c with rightwards arrow on top space equals open vertical bar straight a with rightwards arrow on top close vertical bar squared plus space left parenthesis straight a with rightwards arrow on top. space straight b with rightwards arrow on top plus space straight a with rightwards arrow on top. space straight c with rightwards arrow on top right parenthesis space plus left parenthesis straight b with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight b with rightwards arrow on top. space straight c with rightwards arrow on top right parenthesis space plus space open vertical bar straight b with rightwards arrow on top close vertical bar squared plus space left parenthesis straight c with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top. space straight b with rightwards arrow on top right parenthesis space plus space open vertical bar straight c with rightwards arrow on top close vertical bar squared space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space$
$equals space left parenthesis 3 right parenthesis squared plus 0 plus 0 plus left parenthesis 4 right parenthesis squared plus 0 plus left parenthesis 5 right parenthesis squared space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space of space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis close square brackets space equals space 9 plus 16 plus 25 space equals space 50$
$therefore space space space open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar space equals space square root of 50 space equals space 5 square root of 2$

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Long Answer Type

214. If with reference to the right handed system of mutually perpendicular unit vectors

straight i with hat on top comma space space straight j with hat on top space and space straight k with hat on top comma space space straight alpha with rightwards arrow on top space equals space 3 straight i with hat on top minus straight j with hat on top comma space space straight beta with rightwards arrow on top space equals 2 straight i with hat on top space plus space straight j with hat on top space minus space 3 space straight k with hat on top comma space

then express

straight beta with rightwards arrow on top

in the form

straight beta with rightwards arrow on top space equals space stack straight beta subscript 1 with rightwards arrow on top space plus space straight beta with rightwards arrow on top subscript 2 comma space space where space stack straight beta subscript 1 with rightwards arrow on top space is space parallel space to space straight alpha with rightwards arrow on top space and space stack straight beta subscript 2 with rightwards arrow on top space

is perpendicular to

straight alpha with rightwards arrow on top.

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Multiple Choice Questions

215.

If $straight theta$ is the angle between two vectors $straight a with rightwards arrow on top space and space straight b with rightwards arrow on top$ , then $straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space greater or equal than space 0$ only when

$0 less than straight theta less than straight pi over 2$
$0 less or equal than straight theta less or equal than straight pi over 2$
$0 less than straight theta less than straight pi$
$0 less than straight theta less than straight pi$

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216.

Let $straight a with rightwards arrow on top space and space straight b with rightwards arrow on top$ be two unit vectors and $straight theta$ be the angle between them. Then $straight a with rightwards arrow on top plus straight b with rightwards arrow on top$ is a unit vector if choose the correct answer.