225.
If the median of the base of a triangle is perpendicular on the base, then prove that the triangle is an isosceles.
Let ABC be a triangle in which the median AD is perpendicular to base BC.Take A as origin. Let
![straight b with rightwards arrow on top. space straight c with rightwards arrow on top](/application/zrc/images/qvar/MAEN12067192.png)
be position vectors of B and C so that
![AB with rightwards arrow on top space space equals space straight b with rightwards arrow on top comma space space AC with rightwards arrow on top space equals space straight c with rightwards arrow on top](/application/zrc/images/qvar/MAEN12067192-1.png)
.
Since D is mid-point of BC
![](/application/zrc/images/qvar/MAEN12067192-2.png)
![therefore space space space space space](/application/zrc/images/qvar/MAEN12067192-3.png)
position vector of D is
![fraction numerator straight b with rightwards arrow on top plus straight c with rightwards arrow on top over denominator 2 end fraction](/application/zrc/images/qvar/MAEN12067192-4.png)
i.e.,
![AD with rightwards arrow on top space equals space fraction numerator straight b with rightwards arrow on top plus straight c with rightwards arrow on top over denominator 2 end fraction](/application/zrc/images/qvar/MAEN12067192-5.png)
Also,
![BC with rightwards arrow on top space equals space straight P. straight V. space of space straight C space minus space straight P. straight V. space of space straight B space equals space straight c with rightwards arrow on top minus straight b with rightwards arrow on top](/application/zrc/images/qvar/MAEN12067192-6.png)
Since
![AD perpendicular BC](/application/zrc/images/qvar/MAEN12067192-7.png)
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