Show that the diagonals of a rhombus bisect each other at right

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsLong Answer Type

231.

Prove, using vectors, that the altitudes of a triangle are concurrent.
OR
Prove that the perpendicular from the vertices to the opposite sides of a triangle are concurrent. 

141 Views

Advertisement

232. Show that the diagonals of a rhombus bisect each other at right angles.


Let ABCD be the rhombus. Take A as origin.

    Let straight b with rightwards arrow on top comma space straight d with rightwards arrow on top be the position vectors of B and D respectively so that
                           AB with rightwards arrow on top space equals space straight b with rightwards arrow on top comma space space AD with rightwards arrow on top space equals space straight d with rightwards arrow on top

Now,        AC with rightwards arrow on top space equals space AB with rightwards arrow on top space space plus space BC with rightwards arrow on top space equals space AB with rightwards arrow on top space plus space AD with rightwards arrow on top
                                                               [because BC is equal and parallel to AD]
therefore space space space AC with rightwards arrow on top space equals space straight b with rightwards arrow on top space plus space straight d with rightwards arrow on top
Position vector of mid-point of diagonal AC is fraction numerator 0 with rightwards arrow on top plus left parenthesis straight b with rightwards arrow on top plus straight d with rightwards arrow on top right parenthesis over denominator 2 end fraction space space or space space fraction numerator straight b with rightwards arrow on top plus straight d with rightwards arrow on top over denominator 2 end fraction

Also position vector of mid-point of diagonal BD is fraction numerator straight b with rightwards arrow on top plus straight d with rightwards arrow on top over denominator 2 end fraction

∴    position vector of mid-point of diagonal AC is same as position vector of mid-point of diagonals BD.
∴  diagonals AC and BD bisect each other.
Also,  AC with rightwards arrow on top. space BD with rightwards arrow on top space equals space left parenthesis straight b with rightwards arrow on top plus straight d with rightwards arrow on top right parenthesis. space left parenthesis straight d with rightwards arrow on top space minus space straight b with rightwards arrow on top right parenthesis
                                          open square brackets because space space BD with rightwards arrow on top space equals space straight P. straight V. space of space straight D space minus space straight P. straight V. space of space straight B space equals space straight d with rightwards arrow on top minus straight b with rightwards arrow on top close square brackets

equals space straight d with rightwards arrow on top squared space minus space straight b with rightwards arrow on top squared space equals space AD squared space minus space AB squared
equals space space 0
                                           [because AD = AB as all sides of rhombus are equal]
therefore space space space AC with rightwards arrow on top space is space perpendicular space to space BD with rightwards arrow on top.
therefore diagonals AC and BD are perpendicular to each other. 
Hence the result. 

84 Views

Advertisement
233. In a triangle OAB , ∠AOB = 90°. If P and Q are the points of trisection of AB, prove that OP squared space plus space OQ squared space equals space 5 over 9 AB squared
92 Views

234. In a tetrahedron, if two pairs of opposite edges are perpendicular, then the third pair is also perpendicular to each other and the sum of the sequares of two opposite edges is the same for each pair.
93 Views

Advertisement
235.

Find straight lambda space and space straight mu if  left parenthesis 2 space straight i with hat on top space plus space 6 space straight j with hat on top space plus space 27 space straight k with hat on top right parenthesis space cross times left parenthesis straight i with hat on top space cross times space straight lambda space straight j with hat on top space plus space straight mu space straight k with hat on top right parenthesis space equals space 0 with rightwards arrow on top.

74 Views

 Multiple Choice QuestionsShort Answer Type

236.

Find open vertical bar straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top close vertical bar comma space space space if space space straight a with rightwards arrow on top space equals space 2 space straight i with hat on top space plus straight j with hat on top space plus space 3 straight k with hat on top space and space straight b with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space 5 space straight j with hat on top space minus space 2 space straight k with hat on top.

77 Views

237.

Find open vertical bar straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top close vertical bar  if  straight a with rightwards arrow on top space equals straight i with hat on top space minus space 7 space straight j with hat on top space plus space 7 space straight k with hat on top and straight b with rightwards arrow on top space equals space 3 straight i with hat on top space minus space 2 straight j with hat on top space plus space 2 straight k with hat on top

73 Views

238.

If straight a with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space 3 space straight k with hat on top space and space straight b with rightwards arrow on top space equals 3 space straight i with hat on top space minus space 2 space straight j with hat on top space plus space 2 space straight k with hat on top comma space space find space open vertical bar 2 straight b with rightwards arrow on top cross times space straight a with rightwards arrow on top close vertical bar.

76 Views

Advertisement

 Multiple Choice QuestionsLong Answer Type

239.

If straight a with rightwards arrow on top space equals straight i with hat on top space minus straight j with hat on top space plus space 2 space straight k with hat on top comma space space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space 3 space straight j with hat on top space minus space 4 space straight k with hat on top comma then show that straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top space equals space minus straight b with rightwards arrow on top space cross times space straight a with rightwards arrow on top

73 Views

 Multiple Choice QuestionsShort Answer Type

240. Find a unit vector perpendicular to both straight a with rightwards arrow on top space and space straight b with rightwards arrow on top if  straight a with rightwards arrow on top space equals space 4 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 2 space straight k with hat on top space space and space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 5 space straight j with hat on top space minus space 3 space straight k with hat on top

73 Views

Advertisement