If a = - i^ + j^ + k^ and b = 2i^ + k^, then the vector satisfyin the following conditions
(i) it is coplanar witha and b,
(ii) it is perpendicular to b and
(iii) a · c = 7, is
- i^ + 2j^ + 2k^
- 32i^ + 52j^ + 3k^
- 3i^ + 5j^ + 6k^
- 6i^ + k^
If the vectors b = tanα, - 1, 2sinα2 and c = tanα, tanα, - 3sinα2 are orthagonal and a vector a = 1, 3, sin2α makes an obtuse angle with the Z-axis, then the value of α is
4n + 2π + tan-12
4n + 2π - tan-12
4n + 1π + tan-12
4n + 1π - tan-12
D.
Let b = tanα, - 1, 2sinα2and c = tanα, tanα, - 3sinα2Since, the vector a = 1, 3, sin2α makes an obtuseangle with the the Z-axis. Therefore, its z-componentis negative.i.e., sin2α < 0∴ - 1 ≤ sin2α ≤ 0 ...(i)Since, b and c are orthogonal.∴ b . c = 0⇒ tan2α - tanα - 6 = 0⇒ tanα - 3tanα + 2 = 0⇒ tanα = 3, - 2∴ tanα = 3Then, sin2α = 2tanα1 + tan2α
= 610 > 0, which is contradiction ton Eq. (i)∴ tanα = 3 is not possible.Thus, tanα = - 2 and for this value of tanα, we ettan2α = 2tanα1 - tan2α = 43Since, sin2α < 0 and tanα > 0Therefore, 2α is in third quadrant.Also, sinα2 is meaningful, if 0 < sinα2 < 1.When these conditions are satisfied, α is given byα = 4n + 1π - tan-12
r . i^2 + r . j^2 + r . k^2 is equal to
0
1
r2
3r2
The component of i^ + j^ along j^ and k^ will be
i^ + j^2
j^ + k^2
k^ + i^2
None of these
If a = 2i^ + 5j^ and b = 2i^ - j^, then the unit vector along a + b will be
i^ - j^2
i^ + j^
2i^ + j^
For any vectors, a, b, c a × b + c + b × c + a + c × a + b = ?
a + b + c
[a, b, c]
a × b × c
If a = i^ + 4j^, b = 2i^ - 2j^, c = 5i^ + 9j^, then c is equal to
2a + b
a + 2b
3a + b
a + 3b
If a = i^ + j^ + tk^, b = i^ + 2j^ + 3k^ then the values of 't' for which (a + b) and (a - b) are perpendicular, are
± 2
± 23
±32
± 3
i^ - j^, j^ - k^, k^ - i^ is equal to
2
3
If a . i^ = a . i^ + j^ = ai^ + j^ + k^, then a is equal to
i^
j^
k^
i^ + j^ + k^