If the vectors b = tanα, - 1, 

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 Multiple Choice QuestionsMultiple Choice Questions

741.

If a = - i^ + j^ + k^ and b = 2i^ + k^, then the vector satisfyin the following conditions

(i) it is coplanar witha and b,

(ii) it is perpendicular to b and

(iii) a · c = 7, is

  • - i^ + 2j^ + 2k^

  • - 32i^ + 52j^ + 3k^

  • - 3i^ + 5j^ + 6k^

  • - 6i^ + k^


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742.

If the vectors b = tanα, - 1, 2sinα2 and c = tanα, tanα,  - 3sinα2 are orthagonal and  a vector a = 1, 3, sin2α makes an obtuse angle with the Z-axis, then the value of α is

  • 4n + 2π + tan-12

  • 4n + 2π - tan-12

  • 4n + 1π + tan-12

  • 4n + 1π - tan-12


D.

4n + 1π - tan-12

Let b = tanα, - 1, 2sinα2and c = tanα, tanα,  - 3sinα2Since, the vector a = 1, 3, sin2α makes an obtuseangle with the the Z-axis. Therefore, its z-componentis negative.i.e., sin2α < 0        - 1  sin2α  0        ...(i)Since, b and c are orthogonal. b . c = 0 tan2α - tanα - 6 = 0 tanα - 3tanα + 2 = 0 tanα = 3, - 2  tanα = 3Then, sin2α = 2tanα1 + tan2α

= 610 > 0, which is contradiction ton Eq. (i) tanα = 3 is not possible.Thus, tanα = - 2 and for this value of tanα, we ettan2α = 2tanα1 - tan2α = 43Since, sin2α < 0 and tanα > 0Therefore, 2α is in third quadrant.Also, sinα2 is meaningful, if 0 < sinα2 < 1.When these conditions are satisfied, α is given byα = 4n + 1π - tan-12


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743.

r . i^2 + r . j^2 + r . k^2 is equal to

  • 0

  • 1

  • r2

  • 3r2


744.

The component of i^ + j^ along j^ and k^ will be

  • i^ + j^2

  • j^ + k^2

  • k^ + i^2

  • None of these


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745.

If a = 2i^ + 5j^ and b = 2i^ - j^, then the unit vector along a + b will be

  • i^ - j^2

  • i^ + j^

  • 2i^ + j^

  • i^ + j^2


746.

For any vectors, a, b, c a × b + c + b × c + a + c × a +b = ?

  • 0

  • a + b + c

  • [a, b, c]

  • a × b × c


747.

If a = i^ + 4j^, b = 2i^ - 2j^, c = 5i^ + 9j^, then c is equal to

  • 2a + b

  • a + 2b

  • 3a + b

  • a + 3b


748.

If a = i^ + j^ + tk^, b = i^ + 2j^ + 3k^ then the values of 't' for which (a + b) and (a - b) are perpendicular, are

  • ± 2

  • ± 23

  • ±32

  • ± 3


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749.

i^ - j^, j^ - k^, k^ - i^ is equal to

  • 0

  • 1

  • 2

  • 3


750.

If a . i^ = a . i^ + j^ = ai^ + j^ + k^, then a is equal to

  • i^

  • j^

  • k^

  • i^ + j^ + k^


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