p-toluidine and benzyl amine can be distinguished by from Chemis

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 Multiple Choice QuestionsMultiple Choice Questions

31.

If 'A' is C2H5NH2, 'B' is (C2H5)NH, 'C' is (C2H5)3N, then order of solubility in water is

  • A >B > C

  • B < A <C

  • C < B <A

  • C > B <A


32.

Aniline is resonance hybrid of _ structures.

  • 1

  • 3

  • 5

  • 7


33.

The major product (P) in the following reaction is

CH3CH2NaCN (A) Partial hydrolysisOH- (B) Br2/ KOH (C)

  • CH3CH2.NH2

  • CH3CH2.CO.NHBr

  • CH3.CH2.COONH4

  • CH3.CH2.CO.NBr2


34.

Amine is not formed in the reaction

(i) hydrolysis of RCN
(ii) reduction of RCH = NOH
(iii) hydrolysis of RNC
(iv) hydrolysis of RCONH2

  • (i), (ii) and (iv)

  • (i) and (iv)

  • (ii) and (iii)

  • (i), (ii) and (iii)


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35.

How many sigma and pi-bonds are there in the molecule of dicyanoethene (CN-CH =CH-CN) ?

  • 3 sigma and 3 pi

  • 5 sigma and 2 pi

  • 7 sigma and 5 pi

  • 2 sigma and 3 pi


36.

The final product 'C' in the above reaction is


37.

Select the correct statement(s).

  • LiAlH4 reduces methyl cyanide to methyl amine.

  • Alkaline nitrile has electrophilic as well as nucleophilic centres

  • Saponification is a reversible reaction.

  • Alkaline hydrolysis of methane nitrile forms methanoic acids.


38.

Which of the following compound is the most basic?


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39.

The product formed when phthalimide is treated with a mixture of Br2 and strong NaOH solution is

  • aniline

  • phthalamide

  • phthalic acid

  • anthranilic acid


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40.

p-toluidine and benzyl amine can be distinguished by

  • Sandmeyer's reaction

  • Dye test

  • Molisch test

  • Gattermann reaction


B.

Dye test

p-toluidine contains amino group attached directly to benzene ring, thus undergo diazotisation reaction and gives red dye. In benzyl amine, the amino group is not directly attached to benzene ring. Hence, it will not undergo diazotisation reaction.

                                            ,   

Thus, these two can be distinguished by dye test.


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