Multiple Choice QuestionsWhich one of the following is the strongest base ?
2,4,6-trinitroaniline
2,4,6-trinitro-N,N-dimethyl aniline
N, N-dimethyl aniline
Anline
B.
2,4,6-trinitro-N,N-dimethyl aniline
In 2, 4, 6-trinitro-N,N-dimethylaniline, the bulky nitro substituents at o- position throw the p-orbital of N-atom containing the lone pair of electrons out of the plane of the p-orbitals of the benzene ring. As a result delocalisation of nitrogen electrons on the ring cannot occur. In other words, these electrons are readily available for protonation and hence, it is much stronger base than 2, 4, 6-trinitroaniline, aniline and N,N-dimethylaniline where delocalisation is not inhibited by resonance.
Hinsberg's reagent is
benzene sulphonyl chloride
benzene sulphonic acid
phenyl isocyanide
benzene sulphonamide
The given reaction is called as
Schmidt rearrangement
Curtius rearrangement
Hofmann rearrangement
Lossen rearrangement
Correct basicity of the following compounds are
I. Aniline
II. Pyridine
III. Pyrrole
IV. Guanidine
I >II >III >IV
III >I >II >IV
IV >II >I >III
II >IV>III >I
One amine is more basic than ammonia and the other is less basic than ammonia. The two amines are respectively
N-methyl ethanamine and N, N-dimethyl ethanamine
aniline and N-methyl aniline
N-methyl aniline and aniline
N, N-dimethyl aniline and benzenamine
One of the isomer of C4H11N is optically active. It must be a
primary amine
secondary amine
tertiary amine
all isomers are optically inactive
Which of the following compounds cannot be identified by carbylamine test?
CHCl3
C6H5-NH-C6H5
C6H5NH2
CH3CH2NH2
Acetamide and ethylamine can be distinguished ,by reacting with
Br2 water
acidic KMnO4
aq HCl and heat
aq NaOH and heat
The basicity of aniline is less than that of cyclohexylamine. This is due to :
+R-effect of-NH2 group
-I effect of -NH2 group
-R effect of-NH2 group
hyperconjugation effect
Which of the following would undergo Hofmann reaction to give a primary amine?
R-CO-Cl
RCONHCH3
RCONH2
RCOOR
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