Fluorine reacts with dilute NaOH and forms a gaseous product A. The bond angle in the molecule of A is
104°40'
103°
107°
109°28'
The number of p-d 'pi' bonds present in XeO3 and XeO4 molecules, respectively are-
3, 4
4, 2
2, 3
3, 2
Which one of the following sets correctly represents the increase in the paramagnetic property of the ions?
Cu2+ > V2+ > Cr2+ > Mn2+
Cu2+ < Cr2+ < V2+ < Mn2+
Cu2+ < V2+ < Cr2+ < Mn2+
V2+ < Cu2+ < Cr2+ < Mn2+
Dipole moment of HCl = 1.03 D, HI= 0.38 D. Bond length of HCl = 1.3 Å and HI = 1.6 Å. The ratio of fraction of electric charge, δ, existing on each atom in HCl and HI is
12 : 1
2.7 : 1
3.3 : 1
1 : 3.3
Match the following
Column I (molecules) | Column II ( number of lone pair on central atom) | ||
A | NH3 | 1 | Three |
B | H2O | 2 | Two |
C | XeF2 | 3 | Zero |
D | CH4 | 4 | Four |
5 | One |
A B C D
5 1 3 2
A B C D
3 1 2 5
A B C D
5 1 2 3
A B C D
1 5 3 4
Identify the order in which the spin only magnetic moment (in BM) increases for the following four ions
(I) Fe2+
(II) Ti2+
(III) Cu2+
(IV) V2+
I, II, IV, III
IV, I, II, III
III, IV, I, II
III, II, IV, I
D.
III, II, IV, I
Magnetic moment (μ) is given as-
where, n is number of unpaired electrons:
Fe2+ : [Ar] 3d6; number of unpaired electrons = 4
Ti2+ : [Ar] 3d2; number of unpaired electrons = 2
Cu2+ : [Ar] 3d9; number of unpaired electrons = 1
V2+ : [Ar] 3d3; number of unpaired electrons = 3
Hence, the increasing order of magnetic moment is as- Cu2+ < Ti2+ < V2+ < Fe2+.
The formal charges of N(1), N(2) and O atoms in the following figure are respectively
+1, -1, 0
-1, +1, 0
+1, +1, 0
-1, -1, 0
In which of the following pairs, the central atoms have the same number of lone pairs of electrons?
PCl5, BrF5
XeF2, ICl
XeF4, ClO
SCl4, CH4
Identify the correct set.
Molecule | Hybridisation of central atom | Shape |
PCl5 | dsp3 | square pyramidal |
[Ni(CN)4]2- | sp3 | tetrahedral |
SF6 | sp3d2 | octahedral |
IF3 | dsp3 | pyramidal |
Which one of the following statements is correct?
Hybrid orbitals do not form σ bonds.
Lateral overlap of p-orbitals or p- and d-orbitals produces -bonds.
The strength of bonds follows the order-
σp-p < σs-s < p-p
s-orbitals do not form σ bonds.