Inoic bonds are usually formed by combination of elements with
high ionisation potential and low electron affinity
low ionisation potential and high electron affinity
high ionisation potential and high electron affinity
low ionisation potential and low electron affinity
If a molecule MX3 has zero dipole moment, the sigma bonding orbital used by M (At. no. 13) are
pure p
sp- hybridised
sp2- hybridised
sp3- hybridised
If the value of bond order is zero, then
molecule will be stable
molecule will be unstable
molecule will be in ionic state
None of the above
Which of the following is a proper match?
Shape | |
A. 0.115 - 0.225 | i. Triangular |
B. 0.225 - 0.414 | ii. Tetrahedral |
C. 0.414 - 0.732 | iii. Cubic |
D. 0.732 - 1 | iv. Octahedral |
A - i; B - ii; C - iv; D - iii
A - iii; B - ii; C - iv; D - i
A - i; B - iii; C - ii; D - iv
A - ii; B - iv; C - i; D - iii
According to MOT which of the following is correct for potassium hexa cyano ferrate (III)?
It is octahedral complex.
t2g orbital contains the e- of metal.
For iron, overlapping between empty orbitals and ligand orbitals takes place.
All of the above
D.
All of the above
For the complex [Fe(CN)6]4-
Oxidation state of Fe = +II
Co-ordination number = 6
Electronic configuration of Fe2+ =
1s2, 2s2 2p6, 3s2 3p6 3d6, 4s0 4p0
Since, -CN is ligand of strong field, hence it paired up electrons of d-orbital.
So, [Fe(CN)6]4-
Hybridisation = d2sp3
Magnetic moment = zero
Number of upaired electrons = zero
Geometry = octahedral