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 Multiple Choice QuestionsMultiple Choice Questions

231.

Which of the following is an electron deficient compound?

  • B2H6

  • NH3

  • C2H6

  • CCl4


232.

Which of the following has zero dipole moment?

  • ClF

  • PCl3

  • SiF4

  • CFCl3


233.

The shape of water molecule according to VSEPR theory, is

  • octahedral

  • distorted tetrahedral

  • trigonal planar

  • trigonal bipyramidal


234.

Which of the following species is paramagnetic?

  • CN-

  • NO

  • O22-

  • CO


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235.

XeF4 has a shape of

  • spherical

  • trigonal bipyramidal

  • square planar

  • tetrahedral


236.

In which of the following pairs both molecules do not possess same type of hybridisation?

  • CH4 and H2O

  • PCl5 and SF4

  • SF6 and XeF4

  • BCl3 and NCl3


237.

If H-X bond length is 2.00 Å. and H-X bond has dipole moment 5.12 x 10-30 C-m, the percentage of ionic character in the molecule will be

  • 100%

  • 16%

  • 18%

  • 20%


238.

(i) H—C—H angle in CH4
(ii) Cl—B—Cl angle in BCl3
(iii) F—I—F angle in IF7 in a plane
(iv) I—I—I angle in I3-

Increasing order of above bond angles is

  • (i) < (ii)< (iii)< (iv)

  • (ii)< (i) < (iii)< (iv)

  • (iii)< (i)< (ii)< (iv)

  • (iv)< (ii) < (i) < (iii)


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239.
  • O22-< O2-<O2 <O22+

  • O22-< O2<O2-<O22+

  • O2<O22-< O2-<O22+

  • O2 <O22+<O22-< O2-


A.

O22-< O2-<O2 <O22+

According to MO theory, electronic configuration of

O22+(8+8-2= 14)=σ1s2,σ*1s2,σ2s2,σ*2s2,π2px2π2py2,π2pz2Bond order of O22+=Nb-Na2= 10-42=3O2 (8+ 8 = 16) =σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2, π2px2π2py2,π*2px1π*2py1Bond order of O2=Nb-Na2= 10-62= 2O2-(8+ 8 + 1 = 17)=σ1s2,σ*1s2,σ2s12,σ*2s2,σ2pz2, π2px2π2py2,π*2px1π*2py1BO of O2-= 10-72= 1.5O22- (8+8+2=18),BO of O22-= 10-82=1Hence, the order of increasing bond order is asO22-< O2-<O2 <O22+


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240.

Which of the following is paramagnetic?

  • [Ni(CO)4]2+

  • [Co(NH3)6]2+

  • [Ni(CN)4]2-

  • [NiCl4]2-


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