The number of antibonding electron pairs in O molecular ion on the basis of molecular orbital theory is (Atomic number of O is 18)
5
4
3
2
An octahedral complex is formed when hybrid orbitals of the following type are involved
sp3
dsp2
d2sp3
sp2d2
The angle strain in cyclobutane is
24°44'
29°16'
19°22'
9°44'
D.
9°44'
When carbon is bonded to four other atoms, the angle between any pair of bonds = 109°,28' (tetrahedral angle) but the ring of cyclobutane is square with four angles of 90°. So, deviation of the bond angle (angle strain) in cyclobutane.
= 109° 28' - 90°/2
= 19° 28/ 2 = 9° 44'
The correct statement with regard to is
both are equally stable
both do not exist
H is more stable than H
H is more stable than H