The dipole moment of HBr is 2.60 x 10-30 Cm and the interatomic spacing is 1.41 .The percent ionic character of HBr is:
11.5%
10.1%
8.2%
4.1%
Which of the following gives correct arrangement of compounds involved based on their bond strength ?
HF > HCl > HBr > HI
HI > HBr > HCl > HF
HF > HBr > HCl > HI
HCl > HF > HBr > HI
Hybridization of 1 and 2 carbon atom in
H2 = = CH2 are
sp, sp
sp2, sp2
sp2, sp
sp3, sp2
C.
sp2, sp
In this compound carbon atoms have following hybridization :
Carbon one contains one m bond and carbon two contains two m bonds and hence show sp2 and sp hybridization respectively.
The hybridisation and shape of IF5 are respectively:
sp3d , trigonal bipyramide
sp3d , see saw
sp3d , square pyramidal
sp3d , pentagonal pyramidal
Assuming that Hund's rule in violated,the bond order and magnetic nature of the diatomic molecule B2 is:
1 and diamagnetic
0 and diamagnetic
1 and paramagnetic
O and paramagnetic