The one electron species having ionisation energy of 54.4 eV is

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 Multiple Choice QuestionsMultiple Choice Questions

191.

The radius of H-atom in its ground state is 0.58Å .The radius of, 3Li2+ ithe similar state is

  • 0.1777 Å

  • 0.706 Å

  • 1.06 Å

  • 0.058 Å


192.

The correct order of ionization energies is

  • Cu > Ag > Au

  • Cu > Au > Ag

  • Au > Cu > Ag

  • Ag > Au > Cu


193.

The set representing the correct order of ionic radius is

  • Li+ > Be2+ > Na+ > Mg2+

  • Na+ > Li+ > Mg2+ > Be2+

  • Li+ > Na+ > Mg2+ > Be2+

  • Mg2+ > Be2+ > Li+ > Na+


194.

Which of the following is the correct decreasing order of oxidation state of nitrogen?

  • HNO3 > NO > NH4Cl > N2

  • HNO3 > NO > N2 > NH4Cl

  • HNO3 > NH4Cl > NO > N2

  • NO > HNO3 > NH4Cl > N2


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195.

Which of the following has highest electron affinity?

  • N

  • O

  • F

  • Cl


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196.

The one electron species having ionisation energy of 54.4 eV is

  • He+

  • H

  • Be2+

  • Be3+


A.

He+

Ionisation energy

= -13.6Z2n2eV= -13.6 ×2212  (ForHe+, Z= 2)= -54.4 eV


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197.

Ionisation energy in group 1A varies in the decreasing order as

  • Li > Na > K > Cs

  • Na > Li > K > Cs

  • Li > Cs > K  Na

  • K > Cs > Na > Li


198.

An example of a non-stoichiometric compound is

  • PbO

  • NiO2

  • Al2O3

  • Fe3O4


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199.

The equation used to represents the electron gain enthalpy is

  • X(g) + e- → X-(g)

  • X(s) + e- → X-(g)

  • X(g) → X+(g) + e-

  • X(s) → X+(g) + e-


200.

An element in +2 oxidation state has 24 electrons. The atomic number of the element and the number of unpaired electrons in it respectively are

  • 24 and 4

  • 26 and 4

  • 24 and 2

  • 26 and 5


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