The heat of neutralisation of a strong acid and a strong alkali is 57.0 kJ mol-1.The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is
57.0 kJ
11.4 kJ
28.5 kJ
34.9 kJ
Ammonium acetate which is 0.01 M, is hydrolysed to 0.001 M concentration. Calculate the change in pH in 0.001 M solution, if initially pH = pKa
5
10
100
1
NH4Cl is acidic due to
cationic hydrolysis
anionic hydrolysis
its ionic nature
pH > 7
A.
cationic hydrolysis
NH4Cl + H2O → NH4OH + HCl
or, NH + Cl- + H2O → NH4OH + H+ + Cl-
or, + H2O → NH4OH + H+
Due to the presence of H+, after cationic hydrolysis in the solution, the solution of NH4Cl is acidic.
An acid solution of pH = 6 is diluted 1000 times, the pH of the final solution becomes
6.01
9
3.5
6.99