If the molar solubility of X3B3(AlF6)2 at 298 K is x, the solubility product Ksp is
18x3
27x4
27x8
2916x8
For the equilibrium reaction,
2SO2 (g) + O2 (g) 2SO3 (g) + H
the increase in temperature
favours the formation of SO3
favours the decomposition of SO3
does not affect the equilibrium
stops the reaction
5 millimoles of caustic potash and 5 millimoles of oxalic acid are mixed and dissolved in 100 mL water. The solution will be
basic
acidic
neutral
cannot say
B.
acidic
The equation for the reaction of oxalic acid with a solution of caustic potash.
2KOH (aq) + H2C2O4.2H2O (aq) K2C2O4 (aq) + 4H2O
Molarity equation,
where, M1 = molarity of acid = 5 millimol
M2 = molarity of base = 5 millimol
V1 = volome of acid = 100 mL
V2 = volume of base = 100 mL
n1 = stoichiometric coeffecient of acid = 1
n2 = stoichiometric coeffecient of base = 2
As it is clear from balanced equation that 2 moles of KOH are required to neutralize one mole of oxalic acid. Thus, the solution formed by 5 millimoles of KOH and 5 millimoles of oxalic acid mixed and dissolved in 100 mL water will be acidic.
Which solution is a buffer?
Acetic acid + NaOH (equimolar ratio)
Acetic acid + NaOH (1 : 2 molar ratio)
Acetic acid + NaOH (2 : 1 molar ratio)
HCl + NaOH (equimolar ratio)
If in the reaction N2O4 2NO2: is the degree of dissociation of N2O4 then total number of moles at equilibrium is
(1-α)
(1+α)
(1-α)2
(1+α)2
In the equilibrium mixture, KI+ I2 KI3 the concentration of KI and I2 and three fold respectively . The concentration of KI3 becomes
two fold
three fold
five fold
six fold