Ethyl benzene cannot be prepared by
Wurtz reaction
Wurtz-Fittig reaction
Friedel-Craft's reaction
Clemmensen reduction
Which one of the following is not true for the hydrolysis of t-butyl bromide with aqueous NaOH?
Reaction occurs through the SN1 mechanism
The intermediate formed is a carbocation
Rate of the reaction doubles when the concentration of alkali is doubled
Rate of the reaction doubles when the concentration of t-butyl bromide is doubled
Following is the substitution reaction in which -CN replaces -Cl.
R-Cl + R-CN + KCl
To obtaine propanenitrile, R-Cl should be
chloroethane
1-chloropropane
chloromethane
2-chloropropane
Which of the following is not true for SN1 reaction?
3°-alkyl halides generally react through SN1 reaction
The rate of the reaction does not depend upon the molar concentration of the nucleophile
1°-alkyl halides generally react through SN1 reaction
It is favoured by polar solvents
Match the reactant in Column I with the reaction in Column II.
Column I | Column II |
A. Acetic acid | i. Stephen |
B. Sodium phenate | ii. Friedel Crafts |
C. Methyl cyanide | iii. HVZ |
D. Toulene | iv. Kolbe's |
A - iii; B - i; C - iv; D - ii
A - iv; B - ii; C - iii; D - i
A - ii; B - iii; C - i; D - iv
A - iii; B - iv; C - i; D - ii
An incorrect statement with respect to SN1 and SN2 mechanisms for alkyl halide is
A strong nucleophile in an aprotic solvent increases the rate or favours SN2 reaction.
Competing reaction for an SN2 reaction is rearrangement.
SN1 reactions can be catalysed by some Lewis acids.
A weak nucleophile and a protic solvent increases the rate or favours SN1 reaction.
B.
Competing reaction for an SN2 reaction is rearrangement.
Among the given statements, statement b is the incorrect one.
During SN2 reaction of alkyl halide, inversion of configuration takes place instead of rearrangement. While SN1 reaction occurs through the formation of carbocation intermediate which is favoured by the presence of lewis acid and aprotic solvent. Rearrangement is also possible as
CH3X + KOH (aq) → CH3OH + KX
The hydrolysis of optically active 2-bromobutane with aqueous NaOH result in the formation of
(+) butan -2-ol
(-) butan-2-ol
(±) butan-1-ol
(±) butan-2-ol
Predict the product 'C' in the following series of reactions:
CH3-COOH
CH3CH(OH)C6H5
CH3CH(OH)C2H5
(CH3)2C(OH)C6H5
In Grignard reagent the carbon-magnesium bond is:
electrovalent
covalent
dative
hydrogen bonding