Chlorobenzene is o, p-directing in electrophilic substitution reaction. The directing influence is explained by
+M of Ph
+I of Cl
+M of Cl
-I of Ph
Out of
Relative stabilities order is
4 < 2 < 3 < 1
2 > 4 < 3 < 1
4 < 2 < 1 < 3
2 < 4 < 1 < 3
A.
4 < 2 < 3 < 1
Due to the presence of phenyl group the stabihties of the carbocations 1, 2 and 3 are greater than cation 4, (due to resonance). Further the presence of electron-donating groups on phenyl ring increases the stability of carbocation.
Hence, cation 1 and 3 are more stable than cation 2. Moreover - OMe group shows +M effect which is more prominent than +I effect of -Me group. Thus, cation 1 is more stable than cation 3. So, the correct order is, 4 < 2 < 3 < 1.
CH3MgBr + CH2 = CH-COH Product
It is (1 : 4 addition)
CH2=CH-
CH2OH-CH=CH-CH3
CH3CH2CH2CHO
None of the above
Which one is least reactive in a nucleophilic substitution reaction?
CH3CH2Cl
CH2=CHCH2Cl
CH2=CHCl
(CH3)3CCl
Among the given compound choose the two i.hat yield same carbocation on ionisation.
(ii) and (iv)
(i) and (ii)
(ii) and (iii)
(i) and (iii
An organic compound neither reacts neutral ferric chloride solution nor with Fehling solution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is: