At a particular temperature, the ratio of equivalent conductance

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 Multiple Choice QuestionsMultiple Choice Questions

11.

In a flask, the weight ratio of CH4 (g) and SO2 (g) at 298K and 1 bar is 1 : 2. The ratio of the number of molecules of SO2 (g) and CH4 (g) is

  • 1 : 4

  • 4 : 1

  • 1 : 2

  • 2 : 1


12.

You are supplied with 500 mL each of 2N HCl and SN HCL What is the maximum volume of 3M HCl that you can prepare using only these two solutions?

  • 250 mL

  • 500 mL

  • 750 mL

  • 1000 mL


13.

What will be the normality of the salt solution obtained by neutralising x mL y (N) HCl with y mL x(N) NaOH, and finally adding (x + y) mL distilled water

  • 2(x + y)xy N

  • xy2(x + y)N

  • 2xyx + y N

  • x + yxyN


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14.

At a particular temperature, the ratio of equivalent conductance to specific conductance of a 0.01 N NaCl solution is

  • 105 cm3

  • 10cm3

  • 10 cm3

  • 105 cm2


A.

105 cm3

As we know that, 

Equivalent conductance (λ) = Specific conductance (K) × 1000Concentration

or, λK = 1000conc.

or, λK  = 1000 Ω-1 cm2 eq-10.01Ω-1 cm-1   (Given conc. = 0.01 N)

or, λK = 105 cm3 eq-1


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15.

Commercial sample of H2O2 is labeled as 10 V. Its % strength is nearly

  • 3

  • 6

  • 9

  • 12


16.

The system that contains the maximum number of atoms is

  • 4.25 g of NH3

  • 8 g of O2

  • 2g of H2

  • 4g of He


17.

The volume of ethyl alcohol ( density 1.15 g/cc) that has to be added to prepare 100 cc of 0.5 M ethyl alcohol solution in water is 

  • 1.15 cc

  • 2 cc

  • 2.15 cc

  • 2.30 cc


18.

Which one of the following is wrong about molecularity of a reaction?

  • It may be whole number or fractional

  • It is calculated from reaction mechanism

  • It is the number of molecules of the reactants taking part in a single step chemical reaction

  • It is always equal to the order of elementary reaction


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19.

The amount of the heat released when 20 mL 0.5 M NaOH is mixed with 100 mL 0.1 M HCl is × kJ. The heat of neutralisation is

  • -100 x kJ/mol

  • -50 x kJ/mol

  • + 100 x kJ/mol

  • +50 x kJ/mol


20.

2 g of metal carbonate is neutralised completely by 100 mL of 0.1 N HCl. The equivalent weight of metal carbonate is

  • 50

  • 100

  • 150

  • 200


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