The sample with largest number of atoms is from Chemistry Some B

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 Multiple Choice QuestionsMultiple Choice Questions

141.

If an organic compound has C = 40%, H = 13.3% and N = 46.67%, then the empirical formula of this compound is

  • CH4N

  • C2H8N2

  • CH3N

  • None of these


142.

Which of the following units of energy, represents maximum amount of energy?

  • Calorie

  • Joule

  • Erg

  • Electron volt


143.

A compound has the empirical formula CH2O. Its vapour density is 30. Its molecular formula is

  • C2H4O2

  • C2H6O

  • C2H6O2

  • C2H4O


144.

Combustion of liquid benzene in oxygen occurs as 2C6H6 + 15O2 → 12CO2 + 6H2O. At STP, what volume (in litre) of oxygen is required for the full combustion of 3.9 g liquid benzene?

  • 11.2 L

  • 22.4 L

  • 8.4 L

  • 7.4 L


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145.

64 g of an organic compound contains 24 g of carbon, 8 g of hydrogen and the rest oxygen. The empirical formula of the compound is

  • CH2O

  • C2H4O

  • CH4O

  • C2H8O


146.

1f 20 mL of 0.4 N NaOH solution completely neutralises 40 mL of a dibasic acid, the molarity of the acid solution is

  • 0.1 M

  • 0.2 M

  • 0.3 M

  • 0.4 M


147.

Molality of a solution is equal to

  • number of moles of solutenumber of litres of solution

  • number of g-equivalents of solutenumber of litres of solution

  • number of moles of solutenumber of kilogram of solvent

  • number of moles of a componenttotal number of moles of all components


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148.

The sample with largest number of atoms is

  • 1g O2(g)

  • 1g Ni(s)

  • 1g B(s)

  • 1g N2(g)


C.

1g B(s)

No. of atoms in 1g of    O2(g) = 2 ×132× 6.023 × 1023= 0.38 × 1023No. of atoms in 1g of   Ni(s) =158.2 × 6.023 × 1023=0.10 × 1023No. atoms in 1g of B(s) = 110.8× 6.023 × 1023= 0.56 × 1023No. of atoms in 1g ofN2(g) = 2 × 110.8 ×  6.023 × 1023= 0.43 × 1023Thus, 1 g B(s) contains the largest number of atoms.  


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149.

An organic compound containing C, H and N gives the following on analysis : C = 40%, H = 13.33% and N = 46.67%. What would be its empirical formula?

  • C2H7N

  • C2H7N2

  • CH4N

  • CH3N


150.

The normality of 0.2M H3PO2 is

  • 0.2 N

  • 0.4 N

  • 0.6 N

  • 0.06 N


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