How many moles of O2 can be obtained by electrolysis of 90 g H2O?

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

151.

How many moles of O2 can be obtained by electrolysis of 90 g H2O?

  • 5.0 mol

  • 0.5 mol

  • 2.5 mol

  • 0.25 mol


C.

2.5 mol

The equation representing the elcectrolysis of H2O to form O2 and H2.

2H2O 2 × 18 = 36 gm  2H2At cathode2 mol + O2At anode1 mol

Since, 36 gm of H2O on electrolysis produces 1 mole of O2.

 90 gm of H2O on electrolysis produces 

136 × 90 = 2.5 mol of O2


Advertisement
152.

An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives NH3 gas on heating with NaOH. A can be

  • CH3CONH2

  • C6H5CONH2

  • NH2CONH2

  • CH3NHCONH2


153.

The empirical formula of a compound is CH2. One mole of this compound has a mass 42g. Its molecular formula is

  • C3H6

  • C2H6

  • CH2

  • C2H2


154.

Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together, yield

  • sulphur trioxide and water

  • hydrogen and sulphurous acid

  • sulphur and water

  • hydrogen peroxide and sulphur


Advertisement
155.

3 g of oxide of a metal is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of metal is

  • 12

  • 20

  • 33.25

  • 2.325


156.

4.9 g of H2SO4 is present in 100 mL solution. The molarity and normality of the solution will be

  • Molarity = 1M, Normality= 0.5N

  • Molarity = 1M, Normality= 0.25N

  • Molarity = 0.5M, Normality= 1N

  • Molarity = 2M, Normality= 3N


157.

0.0833 mole of a carbohydrate of empirical formula CH2O contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is.

  • C5H10O5

  • C3H4O3

  • C12H22O11

  • C6H12O6


158.

When 50cm3 of 0.2N H2SO4 is mixed with 50 cm3 of 1N KOH, the heat liberated is

  • 11.46 kJ

  • 57.3 kJ

  • 573 kJ

  • 573 J


Advertisement
159.

Heat liberated with 100 mL of 1 N NaOH is neutralised by 300 mL of 1 N HCl

  • 11.56 kJ

  • 5.73 kJ

  • 22.92 kJ

  • 17.19 kJ


160.

A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is

  • 6N

  • 2N

  • 4N

  • 8N


Advertisement