The empirical formula of a non-electrolyte is CH2O. A solution co

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 Multiple Choice QuestionsMultiple Choice Questions

181.

50 cm3 of 0.2 N HCl is titrated against 0.1 N NaOH solution. The titration was discontinued after adding 50 cm3 of NaOH. The remaining titration is completed by adding 0.5 N KOH. The volume of KOH required for completing the titration is 

  • 12 cm3

  • 10 cm3

  • 21.0 cm3

  • 16.2 cm3


182.

The rms velocity of hydrogen is 7 times the rms velocity of nitrogen. If T is the temperature of the gas, which of the following is true?

  • TH2 = 7  TN2

  • TN2 = TH2

  • TN2 = 7 TH2

  • TN2 = 2TH2


183.

50 cm3 of 0.2 NHCl is titrated against 0.1 N NaOH solution. The titration is discontinued after adding 50 cm3 of NaOH.The remaining titration is completed by adding 0.5 N KOH. The volume of KOH required for completing the titration is

  • 12 cm3

  • 10 cm3

  • 25 cm3

  • 10.5 cm3


184.

1 g of silver gets distributed between 10 cm3 of molten zinc and 100 cm3 of molten lead at 800°C. The percentage of silver in the zinc layer is approximately

  • 89

  • 91

  • 97

  • 94


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185.

Excess of silver nitrate solution is added to 100 mL of 0.01 M pentaaqua chloro chromium (III) chloride solution. The mass of silver chloride obtained in grams is [Atomic mass of silver is 108].

  • 287 × 10-3

  • 143.5 × 10-3

  • 143.5 × 10-2

  • 287 × 10-2


186.

The empirical formula of a non-electrolyte is CH2O. A solution containing 3 g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution. The
molecular formula of the compound is 

  • CH2O

  • C2H4O2

  • C4H8O4

  • C3H6O3


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187.

The empirical formula of a non-electrolyte is CH2O. A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of

  • C2H4O2

  • C3H6O3

  • C5H10O5

  • C4H8O4


D.

C4H8O4

Solutions having same osmotic pressure, at a given temperature, have same concentration.
Concentration of compound = concentration of glucose

6M×1= 0.05M= 60.05= 120Empirical formula mass (CH2O) = 12+ 2+ 16 =30n= molecular massempirical formula massn =12030=4Hence, molecular formula = (CH2O)4 = C4H8O4


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188.

The total number of electrons in 18 mL of water (density = 1 g mL-1) is

  • 6.02 × 1025

  • 6.02 × 1024

  • 6.02 ×  18 × 1023

  • 6.02 × 1023


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189.

The number of water molecules present in a drop of water weighing 0.018 g is

  • 6.022 × 1026

  • 6.022 × 1023

  • 6.022 × 1019

  • 6.022 × 1020


190.

Empirical formula of a compound is CH2O and its molecular mass is 90, the molecular formula of the compound is

  • C3H6O3

  • C2H4O2

  • C6H12O6

  • CH2O


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