0.06% (w/V) aqueous solution of urea is isotonic with from Chemi

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 Multiple Choice QuestionsMultiple Choice Questions

201.

25 cm3 of oxalic acid completely neutralised 0.064 g of sodium hydroxide. Molarity of the oxalic acid solution is

  • 0.064

  • 0.045

  • 0.015

  • 0.032


202.

5.5 mg of nitrogen gas dissolves in 180 g of water at 273 K and 1 atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

  • 1 × 10-6

  • 1 × 10-5

  • 1 × 10-3

  • 1 × 10-4


203.

50 cm3 of 0.04 M K2Cr2O7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M KMnO4 required to oxidize the same amount of H2S gas to sulphur, in acidic medium is 

  • 60 cm3

  • 80 cm3

  • 90 cm3

  • 120 cm3


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204.

0.06% (w/V) aqueous solution of urea is isotonic with

  • 0.06% glucose solution

  • 0.6% glucose solution

  • 0.01M glucose solution

  • 0.1M glucose solution


C.

0.01M glucose solution

0 06% (w/V) aqueous solution of urea =

 0.06100= 6 ×10-4 gThis means that  6 ×10-4 gof urea is present in 1L of solution.Molecular mass of Urea= 60Molarity of urea solution =w ×1000M × volume(mL)                                            =0.06 × 1000100× 60= 0.01M

0 01 M glucose solution is isotonic with 0.06 % (w/V) solution of urea.


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205.

The number of oxygen atoms in 4.4gm of CO2 is

  • 1.2 × 1023

  • 6 × 1022

  • 6 × 1023

  • 12 × 1023


206.

0.30 g of an organic compound containing C, H and oxygen on combustion yields 0.44 g of CO2 and 0.18 g of H2O. If one mole of compound weighs 60, then molecular formula of the compound is

  • CH2O

  • C3H8O

  • C4H6O

  • C2H4O2


207.

What amount of dioxygen (in gram) contains 1.8 × 1022 molecules?

  • 0.0960

  • 0.960

  • 9.60

  • 96.0


208.

An organic compound contains C = 40%, H = 13.33% and N = 46.67%. Its empirical formula is

  • C2H2N

  • C3H7N

  • CH4N

  • CHN


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209.

The mass of BaCO3 produced when excess CO2 is bubbled through a solution of 0.205 mole Ba(OH) is :

  • 81 gm

  • 40.5 gm

  • 20.25 gm

  • 162 gm


210.

A compound contains 54.55% carbon, 9.09% hydrogen, 36.36% oxygen. The empirical formula of this compound is:

  • C3H5O

  • C4H8O2

  • C2H4O2

  • C2H4O


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