35.4 mL of HCl is required for the neutralization of a solution c

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 Multiple Choice QuestionsMultiple Choice Questions

301.

Vapour density of a volatile substance is 4 (CH4 = 1). Its molecular weight would be:

  • 2

  • 8

  • 64

  • 128


302.

20 mL of 0.5 N HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will :

  • be neutral

  • be basic

  • turn phenolphthalein solution pink

  • turn methyl orange red


303.

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is :

  • 182

  • 168

  • 192

  • 188


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304.

35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid is?

  • 0.97 N

  • 0.142 N

  • 0.194 N

  • 0.244 N


C.

0.194 N

We know that 1 gm equivalent weight of NaOH = 40 gm

 40 gm of NaOH = 1 gm equivalent of NaOH

 0.275 gm of NaOH = 140 × 0.275 eq.

                                = 140 × 0.275 × 1000

                                = 6.88 meq

                    N1V1 = N2V2

                N1 × 35.4 = 6.88 (  meq = NV)

                           N1 = 0.194

Therefore, 0.194 N is the normality of HCl. 


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305.

The value of amu is which of the following?

  • 1.57 × 10-24 kg

  • 1.66 × 10-24 kg

  • 1.99 × 10-23 kg

  • 1.66 × 10-27 kg


306.

For a reaction, A + 2B  C, the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is :

  • 5 mol

  • 8 mol

  • 16 mol

  • 4 mol


307.

Mass of one atom is 6.66 x 10-23 g. Its percentage in an hydride is 95.24. Thus , hydride is :

  • MH

  • MH2

  • MH3

  • MH4


308.

Calculate the radius of a water molecule assuming to be spherical (density= 1 g mL-1) :

  • 1.925 10-8 cm

  • 1.925x 10-9 cm

  • 1.925 10-10 cm

  • 1.925 10-11 cm


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309.

When 6 g of a monobasic acid is dissolved in 100 mL solution , it is l N. What is equivalent mass of the acid ?

  • 20 g equiv-1

  • 40 g equiv-1

  • 60 g equiv-1

  • 80 g equiv-1


310.

When 2.495 g of CuSO· x H2O (molar mass 249.5) is heated, 0.05 mole of H2O is lost. Therefore , x is :

  • one

  • three

  • five

  • seven


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