The system that contains the maximum number of atoms is from Che

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 Multiple Choice QuestionsMultiple Choice Questions

341.

36 g water and 828 g ethyl alcohol form an ideal solution. The mole fraction of water in it, is :

  • 1.0

  • 0.7

  • 0.4

  • 0.1


342.

The weight of one molecule of a compound C60H120 is :

  • 1.2 x 10-20 g

  • 5.025 x 1023 g

  • 1.4 x 10-21 g

  • 6.023 x 1023 g


343.

MnO42- (1 mole) in neutral aqueous medium is disproportionated to

  • 2/3 mole of MnO4- and 1/3 mole of MnO2

  • 1/3 mole of MnO4- and 2/3 mole of MnO2

  • 1/3 mole of Mn2O7 and 1/3 mole of MnO2

  • 2/3 mole of Mn2O7 and 1/3 mole of MnO2


344.

Assertion : Effusion rate of oxygen is smaller than nitrogen.

Reason: Molar mass of nitrogen is smaller than oxygen.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false.


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345.

How many litres of ammonia gas at S.T.P. would 1 be needed to prepare 100 ml of 2.5 M ammonium hydroxide solution?

  • 5.6 L

  • 0.056 L

  • 11.2 L

  • 0.56 L


346.

If 0.189 g of a chlorine containing organic compound gave 0.287 g of silver chloride, then the percentage of chlorine in the organic compound is

  • 35.47

  • 35.57

  • 37.57

  • 45.37


347.

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0M HNO3 ? The concentrated acid is 70% HNO3.

  • 45.0 g conc. HNO3

  • 90.0 g con. HNO3

  • 70.0 g conc. HNO3

  • 54.0 g conc. HNO3


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348.

The system that contains the maximum number of atoms is

  • 4.25 g of NH3

  • 8 g of O2

  • 2 g of H2

  • 4 g of He


C.

2 g of H2

Number of atoms = massmolar mass × NA × Number of atoms in 1 mole

Number of atoms in 8 gm

O2832  × NA × 2 = NA2

Number of atoms in 2 gm

H222 × NA × 2 = 2NA

Number of atoms in 4 gm

He = 44 × NA × 1 = NA

Thus, 2 gm H2 contains the maximum number of atoms among the given.


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349.

The weight of oxalic acid that will be required to prepare a 1000 ml (N/20) solution is:

  • 126/100 g

  • 63/40 g

  • 63/20 g

  • 126/20 g


 Multiple Choice QuestionsLong Answer Type

350.

In 'x' mL 0.3 N HCl, the addition of 200 mL distilled water or addition of 100 mL 0.1 N NaOH, gives the same final acid strength. Determine 'x'.


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