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1.
A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu. If e and m are charge and mass of an electron, respectively, then the value of h/λ (where λ is wavelength associated with electron wave) is given by:

2meV

$square root of mev$
$square root of 2 meV end root$
$square root of 2 meV end root$

square root of 2 meV end root

The relation between h/λ and energy is given as:

Applying de-Broglie wavelength and kinetic energy term in eV.

de-Broglie wavelength for an electron (λ) = h/p

⇒ p = h/ λ (i)
Kinetic energy of an electron = eV
As we know that,

From equations (i) and (ii), we get

1081 Views

Which of the following is the energy of a possible excited state of hydrogen?

+13.6 eV
-6.8 eV
-3.4 eV
-3.4 eV

369 Views

The correct set of four quantum numbers for the valence electrons fo rubidium atom (Z = 37) is

5,0,0, +1/2
5,1,0,6+1/2
5,1,1,+1/2
5,1,1,+1/2

510 Views

Energy of an electron is given by
E =- 2.178 x 10^-18 J $open parentheses straight Z squared over straight n squared close parentheses$
Wavelength of light required to excite an electron in a hydrogen atom from level n =1 to n=2 will be (h=6.62 x 10³⁴ Js and c = 3.0 x 10⁸ ms^-1)

1.214 x 10^-7 m
2.816 x 10^-7 m
6.500 x 10^-7 m
6.500 x 10^-7 m

504 Views

The electrons identified by quantum numbers n and l:
(a) n = 4, l = 1 (b) n = 4, l = 0 (c) n = 3, l = 2 (d) n = 3 , l = 1
Can be placed in order of increasing energy as

(c) < (d) < (b) < (a)
(d) < (b) < (c) < (a)
(b) < (d) < (a) < (c)
(b) < (d) < (a) < (c)

366 Views

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emission is at 680 nm, the other is at

1035 nm
325 nm
743 nm
743 nm

283 Views

The ionization energy of He+ is 19.6 x 10–18 J atom^–1. The energy of the first stationary state (n = 1) of Li²⁺ is

4.41 x 10^-16 J atom^–1
-4.41 x 10^-17J atom^–1
-2.2 x 10^-15 J atom^–1.
-2.2 x 10^-15 J atom^–1.

601 Views

The radius of the second Bohr orbit for the hydrogen atom is :
(Plank's const. h = 6.6262 × 10^–34 Js ; mass of electron = 9.1091 × 10–31 kg ; charge of electron
e = 1.60210 × 10^–19 C ; permittivity of vacuum
∈0 = 8.854185 × 10^–12 kg^–1 m^–3 A2)

1.65Å
4.76Å
0.529Å
0.529Å

702 Views

Calculate the wavelength (in nanometer) associated with a proton moving at 1.0 × 10³ms^–1
(Mass of proton = 1.67 × 10^–27 kg and h = 6.63 ×10^–34Js)

0.032 nm
0.40 nm
2.5 nm
2.5 nm

370 Views

10.

In an atom, an electron is moving with a speed of 600m/s with an accuracy of 0.005%. Certainty with which the position of the electron can be located is ( h = 6.6 x10^-34 kgm2s^-1 mass of electron, em= 9.1 x10^-31kg)