The electronic configuration of Cu is from Chemistry Structure o

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

21.

C6H5F18 is a F18  radio-isotope labelled organic compound. F18 decays by positron emission. The product resulting on decay is 

  • C6H5O18

  • C6H5Ar19

  • B12C5H5F

  • C6H5O16


22.

The energy required to break one mole of hydrogen-hydrogen bonds in H2 is 436 kJ. What is the longest wavelength of light required to break a single hydrogen-hydrogen bond?

  • 68.5nm

  • 137nm

  • 274nm

  • 584nm


23.

An element E loses one α and two β particles in three successive stages. The resulting elemenl wiil be

  • an isobar of E

  • an isotone of E

  • an isotope of E

  • E itself


24.

Which one of the following corresponds to a photon of highest energy?

  • λ = 300 mm

  • v = 3 × 108 s-1

  • v = 30 cm-1

  • ε = 6.626 × 10-27 J


Advertisement
25.

The time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is

  • 4m2πr2n2h2

  • n2h24mr2

  • 4π2mr2nh

  • nh4π2mr2


26.

Amongst the following, which should have the highest rms speed at the same temperature?

  • SO2

  • CO2

  • O2

  • H2


27.

The emission spectrum of hydrogen discovered first and the region of the electromagnetic spectrum in which it belongs, respectively are

  • Lyman, ultraviolet

  • Lyman, visible

  • Balmer, ultraviolet

  • Balmer, visible


Advertisement

28.

The electronic configuration of Cu is

  • [Ne] 3s2,3p6,3d9,4s2

  • [Ne] 3s2,3p6, 3d10, 4s1

  • [Ne] 3s2,3p6, 3d3,4s2, 4p6

  • [Ne] 3s2,3p6,3d5,4s2,4p4


B.

[Ne] 3s2,3p6, 3d10, 4s1

Atomic number of Cu is 29.
Thus, its electronic configuration can be written as Cu29 =1s2, 2s2, 2p6, 3s2 3p6, 3d10, 4s1
(Since, fully filled orbitals are more stable, so one electron from 4s orbital transfers into 3d orbital.)
The electronic configuration of neon is Ne10 = 1s2 2s2, 2p6
Thus, using inert gas, the configuration of Cu can also be represented as
Cu29 =[Ne] 3s2, 3p6, 3d10, 4s1


Advertisement
Advertisement
29.

As per de-Broglie's formula a macroscopic particle of mass 100 g and moving at a velocity of 100 cm s-1 will have a wavelength of

  • 6.6 x 10-29 cm

  • 6.6 x 10-30 cm

  • 6.6 x 10-31 cm

  • 6.6 x 10-32 cm


30.

During the emission of a positron from a nucleus, the mass number of the daughter element remains the same but the atomic numbe

  • is decreased by 1 unit

  • is decreased by 2 units

  • is increased by 1 unit

  • remains unchanged


Advertisement