C6H5F18 is a F18 radio-isotope labelled organic compound. F18 decays by positron emission. The product resulting on decay is
C6H5O18
C6H5Ar19
B12C5H5F
C6H5O16
The energy required to break one mole of hydrogen-hydrogen bonds in H2 is 436 kJ. What is the longest wavelength of light required to break a single hydrogen-hydrogen bond?
68.5nm
137nm
274nm
584nm
An element E loses one and two particles in three successive stages. The resulting elemenl wiil be
an isobar of E
an isotone of E
an isotope of E
E itself
Which one of the following corresponds to a photon of highest energy?
λ = 300 mm
v = 3 × 108 s-1
= 30 cm-1
ε = 6.626 × 10-27 J
Amongst the following, which should have the highest rms speed at the same temperature?
SO2
CO2
O2
H2
The emission spectrum of hydrogen discovered first and the region of the electromagnetic spectrum in which it belongs, respectively are
Lyman, ultraviolet
Lyman, visible
Balmer, ultraviolet
Balmer, visible
The electronic configuration of Cu is
[Ne] 3s2,3p6,3d9,4s2
[Ne] 3s2,3p6, 3d10, 4s1
[Ne] 3s2,3p6, 3d3,4s2, 4p6
[Ne] 3s2,3p6,3d5,4s2,4p4
B.
[Ne] 3s2,3p6, 3d10, 4s1
Atomic number of Cu is 29.
Thus, its electronic configuration can be written as Cu29 =1s2, 2s2, 2p6, 3s2 3p6, 3d10, 4s1
(Since, fully filled orbitals are more stable, so one electron from 4s orbital transfers into 3d orbital.)
The electronic configuration of neon is Ne10 = 1s2 2s2, 2p6
Thus, using inert gas, the configuration of Cu can also be represented as
Cu29 =[Ne] 3s2, 3p6, 3d10, 4s1
As per de-Broglie's formula a macroscopic particle of mass 100 g and moving at a velocity of 100 cm s-1 will have a wavelength of
6.6 x 10-29 cm
6.6 x 10-30 cm
6.6 x 10-31 cm
6.6 x 10-32 cm
During the emission of a positron from a nucleus, the mass number of the daughter element remains the same but the atomic numbe
is decreased by 1 unit
is decreased by 2 units
is increased by 1 unit
remains unchanged