The correct set four quantum number for the valence electron of

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 Multiple Choice QuestionsMultiple Choice Questions

271.

The angular momentum of electrons in d orbital is equal to

  • square root of 6 space h
  • square root of 2 straight h
  • 2 square root of 3 straight h
  • 2 square root of 3 straight h
827 Views

272.

What is the maximum number of orbitals that can be identified with the following quantum numbers?

n=3, l =1, m1 = 0

  • 1

  • 2

  • 3

  • 3

4451 Views

273.

Calculate the energy in joule corresponding to light of wavelength 45mm: (Planck's constant h=6.63 x10-34)Js; speed of light c= 3 x 108 ms-1)

  • 6.67 x 1015

  • 6.67 x 1011

  • 4.42 x 10-15

  • 4.42 x 10-15

1495 Views

274.

The value of Planck's constant is 6.63 x 10-34 Js. The speed of light is 3 x1017 nms-1 . Which value is closet to the wavelength in nanometer of a quantum of light with frequency of 6 x 1015 s-1 ?

  • 10

  • 25

  • 50

  • 50

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275.

What is the maximum number of electrons that can be associated with the following set of quantum number?
n=3, l =1 and m=-1.

  • 10

  • 6

  • 4

  • 4

2636 Views

276.

Based on equation
E=-2.178 x 10-18open parentheses straight Z squared over straight n squared close parentheses certain conclusions are written. Which of them is not correct?

  • The negative sign in the equation simply means that the energy of an electron bound to the nucleus is lower than if would be if the electrons were at the infinite distance from the nucleus.

  • Larger the value of n, the larger is the orbit radius

  • Equation can be used to calculate the change in energy when the electron changes orbit

  • Equation can be used to calculate the change in energy when the electron changes orbit

880 Views

277.

Maximum number of electrons in a subshell with l =3 and n=4 is

  • 14

  • 16

  • 10

  • 10

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278.

The correct set four quantum number for the valence electron of rubidium atom (z=37) is 

  • 5,1,1, +1/2

  • 6,0,0,+1/2

  • 5,0,0 +1/2

  • 5,0,0 +1/2


C.

5,0,0 +1/2

37Rb  = 36[Kr] 5s1
Its valence electron is 5s1
so,
n=5
l=0 (for s orbital)
m = 0 ( As m= -l to +l)

s =+1/2

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279.

The orbital angular momentum of p-electron is given as

  • fraction numerator straight h over denominator square root of 2 straight pi end root end fraction
  • square root of 3 fraction numerator h over denominator 2 pi end fraction
  • square root of 3 over 2 end root space h over pi
  • square root of 3 over 2 end root space h over pi
615 Views

280.

The total number of atomic orbitals in fourth energy level of an atom is 

  • 16

  • 32

  • 4

  • 8

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